Thermodynamics Miscellaneous
- Steam enters a well insulated turbine and expands isentropically throughout. At an intermediate pressure, 20 percent of the mass is extracted for process heating and the remaining steam expands isentropically to 9 kPa.
Inlet to turbine: P = 14 MPa, T = 560°C,
h = 3486 kJ/kg, s = 6.6 kJ/(kgK)
Intermediate stage: h = 276 kJ/kg
Exit of turbine: P = 9 kPa, hf = 174 kJ/kg,
hg = 2574 kJ/kg, sf = 0.6 kJ/(kgK), sg = 8.1 kJ/(kgK)
If the flow rate of steam entering the turbine is 100 kg/s, then the work output (in MW) is____.
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h1 = 3486 kJ/kg
h2 = 2776 kJ/kg
s1 = s3 = 6.6
6.6 = .6 + x(0.1 – .6)
x = 0.8
= 2094 kJ/kg
w = (3486 – 2776) + .8 (2776 – 2094)
= 1255.6 kJ/kg = 125.56 MWCorrect Option: B
h1 = 3486 kJ/kg
h2 = 2776 kJ/kg
s1 = s3 = 6.6
6.6 = .6 + x(0.1 – .6)
x = 0.8
= 2094 kJ/kg
w = (3486 – 2776) + .8 (2776 – 2094)
= 1255.6 kJ/kg = 125.56 MW
- For reversible adiabatic compression in a steady flow process, the work transfer per unit mass is
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W ∫vdp for flow process m Correct Option: B
W ∫vdp for flow process m
- A mass m of a perfect gas at pressure p1 and volume V1 undergoes an isothermal process. The final pressure is p2 and volume is V2. The work done on the system is considered positive. If R is the gas constant and T is the temperature, then the work done in the process is
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Wiso = p1V1 in = V2 = mRT In V2 = mRT In p1 = p1v1 In p1 V1 V1 p2 p2 Correct Option: B
Wiso = p1V1 in = V2 = mRT In V2 = mRT In p1 = p1v1 In p1 V1 V1 p2 p2
- Air is held inside a non-insulated cylinder using a piston (mass M = 25 kg and area A = 100 cm²) and stoppers (of negligible area), as shown in the figure. The initial pressure P1 and temperature T1 of air inside the cylinder are 200 kPa and 400° C1 respectively, The ambient pressure P∞ and temperature T∞ are 100 kPa and 27° C respectively. The temperature of the air inside the cylinder (°C) at which the piston will begin to move is ________(correct to two deeimal places).
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Pin = Pamb + mg = 100 + 25 × 4.81 × 10-3 A 100 × 10-4
P2 = 124.525P1 = P2 T1 T2
Correct Option: C
Pin = Pamb + mg = 100 + 25 × 4.81 × 10-3 A 100 × 10-4
P2 = 124.525P1 = P2 T1 T2
- Steam enters a turbine at 30 bar, 300°C (u = 2750 kJ/kg, h = 2993 kJ/kg) and exits the turbine as saturated liquid at 15 kPa (u = 225 kJ/kg, h = 226 kJ/kg). Heat loss to the surrounding is 50 kJ/kg of steam flowing through the turbine. Neglecting changes in kinetic energy and potential energy, the work output of the turbine (in kJ/kg of steam) is______.
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Work output = (2993 – 226.50) kJ/kg = 2717 kJ/kg
Correct Option: B
Work output = (2993 – 226.50) kJ/kg = 2717 kJ/kg