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A mass m of a perfect gas at pressure p1 and volume V1 undergoes an isothermal process. The final pressure is p2 and volume is V2. The work done on the system is considered positive. If R is the gas constant and T is the temperature, then the work done in the process is
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- p1V1 In V2/V1
- –p1V1 In ρ
/ρ2 - –mRT In V2/V1
- –mRT In ρ
/ρ2
Correct Option: B
Wiso = p1V1 in = | = mRT In | = mRT In | = p1v1 In | ||||
V1 | V1 | p2 | p2 |