Advanced Microprocessors

Advanced Microprocessors

Easy Questions

Microprocessor

8085 Microprocessors
Advanced Microprocessors
  1. Convert (205)10 = (x)16?








  1. View Hint View Answer Discuss in Forum

    16) 205 (12 → C
         192
         13 → D
    So, (205)10 = (CD)16 = (x)16
    Therefore, x = CD.

    Correct Option: A

    16) 205 (12 → C
         192
         13 → D
    So, (205)10 = (CD)16 = (x)16
    Therefore, x = CD.

  1. The binary B3 B2 B1 B0 is to be converted to Gray code. The binary digit that does not require a gate for conversion is—








  1. View Hint View Answer Discuss in Forum

    Binary to Gray code converter is shown below:

    From above figure w e conclude that B3 does not require any gate. Hence alternative (B) is the correct answer.

    Correct Option: B

    Binary to Gray code converter is shown below:

    From above figure w e conclude that B3 does not require any gate. Hence alternative (B) is the correct answer.

  1. How many NAND gates are required to make AB + BA?








  1. View Hint View Answer Discuss in Forum


    Y = AB + AB
    This means, half adder requires 4 NAND gates. Hence alternative (C) is the correct answer.

    Correct Option: C


    Y = AB + AB
    This means, half adder requires 4 NAND gates. Hence alternative (C) is the correct answer.

  1. The 2 × 1 MUX having switching delay of 1μ sec connected as shown:

    The output is connected to its own select switch. The output will be—








  1. View Hint View Answer Discuss in Forum

    Here switching delay means after 1 μ sec.,the switch is moved between the point A and B.

    Hence, Time period = 2μ sec
    ∴

    Frequency =
    1
    		 = 0.5 MHz
    2 μsec

    Hence alternative (B) is the correct answer.

    Correct Option: B

    Here switching delay means after 1 μ sec.,the switch is moved between the point A and B.

    Hence, Time period = 2μ sec
    ∴

    Frequency =
    1
    		 = 0.5 MHz
    2 μsec

    Hence alternative (B) is the correct answer.

  1. Write output—








  1. View Hint View Answer Discuss in Forum


    F1 = (AB)′
    F2 = (BA)′
    Y = F1F2 = [( AB)′ ( BA)′]′
    = [(A + B′) ( B + A)] ′ = AB + BA
    Alternative Method:
    NAND-NAND circuit can be replaced by AND-OR Hence,

    Now, F1 = AB,
    F2 = BA
    Y=F1 + F2 = AB + BA (this is shortcut method).

    Correct Option: D


    F1 = (AB)′
    F2 = (BA)′
    Y = F1F2 = [( AB)′ ( BA)′]′
    = [(A + B′) ( B + A)] ′ = AB + BA
    Alternative Method:
    NAND-NAND circuit can be replaced by AND-OR Hence,

    Now, F1 = AB,
    F2 = BA
    Y=F1 + F2 = AB + BA (this is shortcut method).