Advanced Microprocessors
- The number of Boolean function that can be generated by n variables is equal to—
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22n are the number of Boolean function that can be generated by variable. For example if n = 2 ⇒ 222 = 24 = 16 function.
Correct Option: B
22n are the number of Boolean function that can be generated by variable. For example if n = 2 ⇒ 222 = 24 = 16 function.
- The period of the output wave form for the circuit of figure shown, when triggered by a negative pulse is—
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This circuit work as monostable multivibrator Time period = T= 1·1 RC (seconds)
= 1·1 × 7·5 × 103 × 0·1 × 10–6 = 0·825 msCorrect Option: B
This circuit work as monostable multivibrator Time period = T= 1·1 RC (seconds)
= 1·1 × 7·5 × 103 × 0·1 × 10–6 = 0·825 ms
- The combinational logic circuit shown in given figure has an output Q which is—
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Output of MUX, Q = A BC + AB + AB + AB
Multiply by (C + C) the term which contain no C term:
∴ C + C=1
Q = A BC + AB (C + C) + AB (C + C) + ABC (C + C)
or Q = A BC + ABC + ABC + ABC + AB C + ABC + AB C
This can be simplified by K-map, from K-map
Q = A + B + C
Hence alternative (B) is the correct answer.
Alternative Method:
Output of Mux, Q = A BC + AB + AB + AB
or
Q = A (BC + B) + A (B+ B)
or
Q = A (B + C) + A {∵ BC + B = B + C}
or
Q = AB + AC + A {∵B + B = 1}
or
Q = AB + A +AC {∵ AB + A = A + B}
or
Q = A + B + AC
or
Q = AC + A + B
or
Q = A + C + B {∵ AC + A = A + C}
or
Q = A + B + CCorrect Option: B
Output of MUX, Q = A BC + AB + AB + AB
Multiply by (C + C) the term which contain no C term:
∴ C + C=1
Q = A BC + AB (C + C) + AB (C + C) + ABC (C + C)
or Q = A BC + ABC + ABC + ABC + AB C + ABC + AB C
This can be simplified by K-map, from K-map
Q = A + B + C
Hence alternative (B) is the correct answer.
Alternative Method:
Output of Mux, Q = A BC + AB + AB + AB
or
Q = A (BC + B) + A (B+ B)
or
Q = A (B + C) + A {∵ BC + B = B + C}
or
Q = AB + AC + A {∵B + B = 1}
or
Q = AB + A +AC {∵ AB + A = A + B}
or
Q = A + B + AC
or
Q = AC + A + B
or
Q = A + C + B {∵ AC + A = A + C}
or
Q = A + B + C
- To realise the given truth table from the circuit shown in figure, the input to J in terms of A and B would be—
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From truth table if we form K map, we get
J = AB + AB = B (A + A) = BCorrect Option: C
From truth table if we form K map, we get
J = AB + AB = B (A + A) = B
- An OR gate has 6 inputs. How many input words are there in its truth table?
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Number of input = 6
Number of words = 26 = 64
Hence alternative (C) is the correct answer.Correct Option: C
Number of input = 6
Number of words = 26 = 64
Hence alternative (C) is the correct answer.