Mechanical and structural analysis miscellaneous
Direction: A rigid beam is hinged at one end and supported on linear elastic springs (both having a stiffness of ‘k’) at points ‘1’ and ‘2’ and an inclined load acts at ‘2’, as shown.
- Which of the following options represents the deflections δ1 and δ2 at points ‘1’ and ‘2’?
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Taking moment about hinge.
MH = 0
kδ1 + kδ2.2L = p × 2L
∴ kδ1 + 2kδ2 = 2P
From the figure,
⇒ δ2 = 2 × δ1
(since the distance is l for both)∴ δ1 = 2p , δ2 4p 5k 5k Correct Option: B
Taking moment about hinge.
MH = 0
kδ1 + kδ2.2L = p × 2L
∴ kδ1 + 2kδ2 = 2P
From the figure,
⇒ δ2 = 2 × δ1
(since the distance is l for both)∴ δ1 = 2p , δ2 4p 5k 5k
Direction: In the cantilever beam PQR shown in figure below, the segment PQ has flexural rigidity EI and segment QR has infinite flexural rigidity.
- The deflection of the beam at ‘R’ is
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Deflection at
R = 5WL3 + 3W.L2.L 6EI 2EI = 7WL3 3II Correct Option: C
Deflection at
R = 5WL3 + 3W.L2.L 6EI 2EI = 7WL3 3II
- The deflection and slope of the beam at ‘Q’ are respectively
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Deflection at
Q = WL3 + (WL) × L2 3EI 2EI = 5WL3 7EI
Slope atQ = WL2 + WL.L 2EI EI = 3WL2 2EI Correct Option: A
Deflection at
Q = WL3 + (WL) × L2 3EI 2EI = 5WL3 7EI
Slope atQ = WL2 + WL.L 2EI EI = 3WL2 2EI
Direction: Beam GHI is supported by three pontoons as shown in the figure below. The horizontal cross-sectional area of each pontoon is 8 m2, the flexural rigidity of the beam is 10000 kN–m2 and the unit weight of water is 10 kN/m3.
- When the middle pontoon is brought back to its position as shown in the figure above, the reaction at H will be
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δ = (P - R)L3 48EI
x × A × rw = R'
(buoyant force, R' = RG = R1)
⇒ x × A × w = R'∴ x = R' 80
2R' + R = 48
(x + δ).A × δω = R
∴ (x + δ) × 8 × 10 = R⇒ 48 - R + δ = R 2 × 80 80 δ = 3R - 48 160 = (48 - R) × 103 = 19.2kN 48 × 104 Correct Option: C
δ = (P - R)L3 48EI
x × A × rw = R'
(buoyant force, R' = RG = R1)
⇒ x × A × w = R'∴ x = R' 80
2R' + R = 48
(x + δ).A × δω = R
∴ (x + δ) × 8 × 10 = R⇒ 48 - R + δ = R 2 × 80 80 δ = 3R - 48 160 = (48 - R) × 103 = 19.2kN 48 × 104
- When the middle pontoon is removed, the deflection at H will be
-
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Consider that middle position is removed.
Reaction, cluts RG = RI = 24 km (48/2)
This is supported by flotation.
∴ A.rω.rω × h = 24
8 × 10 × h = 24
h = 0.3 m
Deflection at H= PL3 48EI
(similar to a simply supported beam)= 48 × 103 = 0.1 m 48 × 10000
∴ Total deflection = 0.1 + 0.3 = 0.4 mCorrect Option: B
Consider that middle position is removed.
Reaction, cluts RG = RI = 24 km (48/2)
This is supported by flotation.
∴ A.rω.rω × h = 24
8 × 10 × h = 24
h = 0.3 m
Deflection at H= PL3 48EI
(similar to a simply supported beam)= 48 × 103 = 0.1 m 48 × 10000
∴ Total deflection = 0.1 + 0.3 = 0.4 m