Simplification
- In an examination, a student was asked to find (3/14) of a certain number, by mistake he found (3/4) of it. His answer was 150 more then the correct answer. The given number is ?
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∵ 3N/4 - 3N/14 =150
⇒ 15N/28 = 150Correct Option: C
∵ 3N/4 - 3N/14 =150
⇒ 15N/28 = 150
∴ N = (150 x 28) /15 = 280
- If we multiply a fraction by itself and divided the product by its reciprocal, the fraction thus obtained is 1826/27. The original fraction is ?
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∴ N x N x 1/N = 1826/27
⇒ N3 = 512/27
⇒ N3= (8/3)3Correct Option: B
∴ N x N x 1/N = 1826/27
⇒ N3 = 512/27
⇒ N3= (8/3)3
∴ N = 8/3 = 22/3
- The smallest fraction which should be subtracted from the sum of 13/4, 21/2, 57/12, 31/3 and 21/4 to make the result a whole number is ?
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∴ 7/4 + 5/2 + 67/12 + 10 + 9/4 = (21 + 30 + 67 + 40 + 27/12) = 185/12
This is nearly greater than 15. Let required fraction be x.
Then, 185/12 - x = 15Correct Option: A
∴ 7/4 + 5/2 + 67/12 + 10 + 9/4 = (21 + 30 + 67 + 40 + 27/12) = 185/12
This is nearly greater than 15. Let required fraction be x.
Then, 185/12 - x = 15
∴ x = (185/12) - 15
= 5/12
- Gopal was asked to find 7/9 of a fraction. But he made a mistake of dividing the given fraction by 7/9 and got an answer which exceeded the correct answer by 8/21. The correct answer is ?
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∵ Let the fraction = N
∵ (9 x N)/7 - (7 x N)/9 = 8/21Correct Option: B
∵ Let the fraction = N
∵ (9 x N)/7 - (7 x N)/9 = 8/21
⇒ (32 x N)/63 = 8/21
⇒ N = (8/21) x (63/32) = 3/4
∴ Correct answer = N x 7/9 = 7/9 x 3/4 = 7/12
- The highest score in an innings was 3/11 of the total and the next highest was 3/11 of the remainder. If the scores differed by 9, then the total score is ?
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Let total score be N.
Then highest score = 3N/11
Remainder = (N - 3N/11) = 8N/11
Next highest score = 3/11 of 8N/11 = 24N/121
Now, ∵ 3N/11 - 24N/121 = 9
⇒ 9N/121 = 9Correct Option: C
Let total score be N.
Then highest score = 3N/11
Remainder = (N - 3N/11) = 8N/11
Next highest score = 3/11 of 8N/11 = 24N/121
Now, ∵ 3N/11 - 24N/121 = 9
⇒ 9N/121 = 9
∴N = 121