Simplification
- In a family, the father took 1/4 of the cake and he had 3 times as much as others had. The total number of family members is ?
-
View Hint View Answer Discuss in Forum
Let there be N members, other than father .
Father's share = 1/4, other's share = 3/4.
Each of other's share = 3/4NCorrect Option: C
Let there be N members, other than father .
Father's share = 1/4, other's share = 3/4.
Each of other's share = 3/4N
∵ 3 x 3/4N = 1/4
∴ N = 9
Hence, the total number of members = N + 1 = 10
- Ravi earns twice as much in January as in each of the other months. What part of his annual earnings he earns in that month ?
-
View Hint View Answer Discuss in Forum
Suppose Ravi earns Rs. N in each of the 11 months.
Then earning in January = Rs. 2 x N.
∴ Total annual income = (11 x N + 2 x N) = Rs. 13 x NCorrect Option: A
Suppose Ravi earns Rs. N in each of the 11 months.
Then earning in January = Rs. 2 x N.
∴ Total annual income = (11 x N + 2 x N) = Rs. 13 x N
Part of total earning in January = (2 x N) / (13 x N) = 2/13
- √132 + 28 / 4 - (3)3 + 107 = (?)2
-
View Hint View Answer Discuss in Forum
(?)2 = √132 + 28 / 4 - (3)3 + 107
= √169 + 7 - 27 + 107
Correct Option: D
(?)2 = √132 + 28 / 4 - (3)3 + 107
= √169 + 7 - 27 + 107
= √256
= √16
= 4
- If a2 + b2 = 234 and ab = 108, find the value of a + b / a - b . ?
-
View Hint View Answer Discuss in Forum
We know that, (a + b)2 = a2 + b2 + 2ab
= 234 + 2 x 108 = 450
(a - b)2 = a2 + b2 - 2ab
= 234 - 2 x 108 = 18
∴ (a + b)2/(a - b)2 = 450/18 = 25Correct Option: C
We know that, (a + b)2 = a2 + b2 + 2ab
= 234 + 2 x 108 = 450
(a - b)2 = a2 + b2 - 2ab
= 234 - 2 x 108 = 18
∴ (a + b)2/(a - b)2 = 450/18 = 25
⇒ [(a + b)/(a - b)]2 = 25
∴ (a + b)/(a - b) = √25 = 5
- If a2 + 1 = a, then the value of a12 + a6 + 1 is ?
-
View Hint View Answer Discuss in Forum
a2 + 1 = a
⇒ a + 1/a = 1
On squaring both sides, we get
a2 + 1/a2 + 2 = 1
On cubing both sides, we get
(a2 + 1/a2)3 = (-1)3Correct Option: B
a2 + 1 = a
⇒ a + 1/a = 1
On squaring both sides, we get
a2 + 1/a2 + 2 = 1
On cubing both sides, we get
(a2 + 1/a2)3 = (-1)3
⇒ a6 + 1/a6 + 3a2 x 1/a2 (a2 + 1/a2) = -1
⇒ a6 + 1/a6 + 3 x (-1) = -1
Now, a6 + 1/a6 + 1 = 3
As, a12 + a6 + 1 can be written as a6 + 1/a6 + 1
∴ a12 + a6 + 1 = 3