Simplification


  1. In a family, the father took 1/4 of the cake and he had 3 times as much as others had. The total number of family members is ?









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    Let there be N members, other than father .
    Father's share = 1/4, other's share = 3/4.
    Each of other's share = 3/4N

    Correct Option: C

    Let there be N members, other than father .
    Father's share = 1/4, other's share = 3/4.
    Each of other's share = 3/4N
    ∵ 3 x 3/4N = 1/4
    ∴ N = 9
    Hence, the total number of members = N + 1 = 10


  1. Ravi earns twice as much in January as in each of the other months. What part of his annual earnings he earns in that month ?









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    Suppose Ravi earns Rs. N in each of the 11 months.
    Then earning in January = Rs. 2 x N.
    ∴ Total annual income = (11 x N + 2 x N) = Rs. 13 x N

    Correct Option: A

    Suppose Ravi earns Rs. N in each of the 11 months.
    Then earning in January = Rs. 2 x N.
    ∴ Total annual income = (11 x N + 2 x N) = Rs. 13 x N
    Part of total earning in January = (2 x N) / (13 x N) = 2/13



  1. 132 + 28 / 4 - (3)3 + 107 = (?)2









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    (?)2 = √132 + 28 / 4 - (3)3 + 107
    = √169 + 7 - 27 + 107

    Correct Option: D

    (?)2 = √132 + 28 / 4 - (3)3 + 107
    = √169 + 7 - 27 + 107
    = √256
    = √16
    = 4


  1. If a2 + b2 = 234 and ab = 108, find the value of a + b / a - b . ?









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    We know that, (a + b)2 = a2 + b2 + 2ab
    = 234 + 2 x 108 = 450
    (a - b)2 = a2 + b2 - 2ab
    = 234 - 2 x 108 = 18
    ∴ (a + b)2/(a - b)2 = 450/18 = 25

    Correct Option: C

    We know that, (a + b)2 = a2 + b2 + 2ab
    = 234 + 2 x 108 = 450
    (a - b)2 = a2 + b2 - 2ab
    = 234 - 2 x 108 = 18
    ∴ (a + b)2/(a - b)2 = 450/18 = 25
    ⇒ [(a + b)/(a - b)]2 = 25
    ∴ (a + b)/(a - b) = √25 = 5



  1. If a2 + 1 = a, then the value of a12 + a6 + 1 is ?









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    a2 + 1 = a
    ⇒ a + 1/a = 1
    On squaring both sides, we get
    a2 + 1/a2 + 2 = 1
    On cubing both sides, we get
    (a2 + 1/a2)3 = (-1)3

    Correct Option: B

    a2 + 1 = a
    ⇒ a + 1/a = 1
    On squaring both sides, we get
    a2 + 1/a2 + 2 = 1
    On cubing both sides, we get
    (a2 + 1/a2)3 = (-1)3
    ⇒ a6 + 1/a6 + 3a2 x 1/a2 (a2 + 1/a2) = -1
    ⇒ a6 + 1/a6 + 3 x (-1) = -1
    Now, a6 + 1/a6 + 1 = 3
    As, a12 + a6 + 1 can be written as a6 + 1/a6 + 1
    ∴ a12 + a6 + 1 = 3