Network theory miscellaneous
Direction: Statement for Q. 103 to Q. 105. A signal generator supplies a sine wave of 20V, 5kHz to the circuit shown below—

- Calculate total current IT—
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The given circuit:
Capacitive reactance,XC = 1 = 1 2πfC 6·28 × 5 × 103 × 0·2 × 10–6
= 159·2ΩIR = Vs = 20 = 0·2A R 100 IR = VS = 20 = 0·126A XC 159·2
The total current (IT) in parallel circuit is the vector sum of the branch currents. i.e.
IT = IC.IR + j IC = (0·2 + j 0·126)A
or
IT = 0·24 33°Correct Option: A
The given circuit:
Capacitive reactance,XC = 1 = 1 2πfC 6·28 × 5 × 103 × 0·2 × 10–6
= 159·2ΩIR = Vs = 20 = 0·2A R 100 IR = VS = 20 = 0·126A XC 159·2
The total current (IT) in parallel circuit is the vector sum of the branch currents. i.e.
IT = IC.IR + j IC = (0·2 + j 0·126)A
or
IT = 0·24 33°
- The equivalent impedance?
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The given circuit:
Zeq = 10 + 20 || jXL
where XL = 2πf L = 2π × 50 × 0·1 = 31·42Ω
Now,Zeq = 10 + 20 × j (31·42) 20 + j31·42
= 10 + 16·87 32·48°
or
Zeq = 24·23 × j 9·06
or
Zeq = 25·87 20·5°Correct Option: B
The given circuit:
Zeq = 10 + 20 || jXL
where XL = 2πf L = 2π × 50 × 0·1 = 31·42Ω
Now,Zeq = 10 + 20 × j (31·42) 20 + j31·42
= 10 + 16·87 32·48°
or
Zeq = 24·23 × j 9·06
or
Zeq = 25·87 20·5°
- Current I?
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I = Vs = 20 Zeq 25·87 20·5°
= 0·77 –20·5°Correct Option: A
I = Vs = 20 Zeq 25·87 20·5°
= 0·77 –20·5°
- The phase angle between voltage and current—
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θ = 20·5°
Correct Option: A
θ = 20·5°
- The total reactance of a series RLC circuit at resonance—
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The total reactance of a series RLC circuit at resonance is zero.
Correct Option: D
The total reactance of a series RLC circuit at resonance is zero.