Network theory miscellaneous

Network theory miscellaneous

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Network Theory

Network Elements and the Concept of Circuit
Network theory miscellaneous
  1. For the circuit shown below, V1 = 40V when R is 10Ω. When R is 0 Ω, the value of V2 will be —










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    The given circuit:

    From given circuit we conclude that voltage at node 1, i.e. V1 is independent from the resistance R. When R is 0 Ω, the value of V2 will be 40V.

    Correct Option: A

    The given circuit:

    From given circuit we conclude that voltage at node 1, i.e. V1 is independent from the resistance R. When R is 0 Ω, the value of V2 will be 40V.

  1. The value of VA in the circuit shown in the given figure is—










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    The given circuit:

    KCL at node B, we get

    VB
    		 +
    VB + 3
    		 = 3
    11

    or
    2VB + 3 = 3
    VB = 0V
    Therefore,
    VA = 3 × 1 = 3V
    Hence alternative (C) is the correct choice.

    Correct Option: C

    The given circuit:

    KCL at node B, we get

    VB
    		 +
    VB + 3
    		 = 3
    11

    or
    2VB + 3 = 3
    VB = 0V
    Therefore,
    VA = 3 × 1 = 3V
    Hence alternative (C) is the correct choice.

  1. A network with independent sources and resistors shown above in figure (a) has a Thevenin voltage VT and Thevenin resistance RT. What are the Norton equivalent current IN and resistance RN in the figure (b)?










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    The given circuit:

    From figure,

    IN =
    VT
    RT

    and
    RN = RT
    Where, V
    T = Thevenin voltage
    RN = Norton resistance

    Correct Option: B

    The given circuit:

    From figure,

    IN =
    VT
    RT

    and
    RN = RT
    Where, V
    T = Thevenin voltage
    RN = Norton resistance

  1. Two coils having self-inductances of 0·09H and 0·1H and a mutual inductance of 0·015H. The coefficient of coupling between the coils is—








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    From relation, mutual inductance:
    M = K L1L2
    Given,
    M = 0·015H, L1 = 0·09H, L2 = 0·01H
    K=?
    Now, 0·015 = K 0·09 × 0·01
    or
    K = 0·5

    Correct Option: B

    From relation, mutual inductance:
    M = K L1L2
    Given,
    M = 0·015H, L1 = 0·09H, L2 = 0·01H
    K=?
    Now, 0·015 = K 0·09 × 0·01
    or
    K = 0·5

  1. The effective inductance of the circuit shown below—










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    The given circuit:

    Leq = L1 + L2 + L3 – 2M12 + 2M23
    Where L1 = 8H, L2 = 10H, L3 = 6H, M12 = 4H, M23 = 5H
    Now, Leq = 8 + 10 + 6 – 2 × 4 + 2 × 5
    = 24 – 8 + 10 = 26H

    Correct Option: B

    The given circuit:

    Leq = L1 + L2 + L3 – 2M12 + 2M23
    Where L1 = 8H, L2 = 10H, L3 = 6H, M12 = 4H, M23 = 5H
    Now, Leq = 8 + 10 + 6 – 2 × 4 + 2 × 5
    = 24 – 8 + 10 = 26H