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  1. If tan θ + cot θ = 2, then the value of tan100θ + cot100θ is
    1. 2
    2. 0
    3. 1
    4. 3
Correct Option: A

tan θ + cot θ = 2

⇒ tan θ +
1
= 2
tan θ

⇒ tan²θ + 1 = 2 tanθ
⇒ tan²θ – 2tan θ + 1 = 0
⇒ (tanθ – 1)² = 0
⇒ tan θ = 1
∴ cot θ =
1
= 1
tan θ

∴ tan100 θ + cot100 θ = 1 + 1 = 2



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