Home » Aptitude » Trigonometry » Question
  1. If tan θ = 2, then the value of
    8sinθ + 5cosθ
    is :
    sin3θ + 2cos3θ + 3 cosθ
    1. 21
      5
    2. 8
      5

    3. 7
      5
    4. 16
      5

Correct Option: A

Expression

=
8 sin θ + 5 cos θ
sin3θ + 2cos3θ + 3cos θ

Dividing numerator and denominator by cos θ,
=
8 tan θ + 5
tan θ . sin²θ + 2cos²θ + 3

=
8 tan θ + 5
2sin² θ + 2cos²θ + 3

=
8 tan θ + 5
2(sin² θ + 2cos²θ) + 3

=
8 × 2 + 5
=
21
55



Your comments will be displayed only after manual approval.