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A 1.6 m tall observer is 45 metres away from a tower. The angle of elevation from his eye to the top of the tower is 30°, then the height of the tower in metres is (Take √3 = 1.732)
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- 25.98
- 26.58
- 27.58
- 27.98
Correct Option: C
AB = Height of observer = 1.6 metre
CD = Height of tower = h metre
∴ DE = (h – 1.6) metre ; BC = AE = 45 metre
∠ DAE = 30°
| ∴ tan30° | AE |
| ⇒ | = | √3 | 45 |
| ⇒ h - 1.6 = | = 15√3 | √3 |
⇒ h – 1.6 = 15 × 1.732 = 25.98
⇒ h = (25.98 + 1.6) metre
= 27.58 metre
