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The top of a broken tree touches the ground at a distance of 15 metre from its base. If the tree is broken at a height of 8 metre from the ground, then the actual height of the tree is
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- 17 metre
- 20 metre
- 25 metre
- 30 metre
Correct Option: C
Let AB = height of tree = h metre
AC = 8 metre,
BC = CD = Broken part of tree
AD = 15 metre
In ∆ACD,
CD² = AC² + AD² = 8² + 15²
= 64 + 225 = √289
∴ CD = 289 = 17 metre
∴ Original height of tree
= 17 + 8 = 25 metre
