Table chart
Direction: Study the following table and answer the questions.
Number of students from various schools playing various games.
One student plays one game only.
- The difference between the total number of students playing Basketball from all the school and the total number of students playing Cricket from all the schools is :
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As per given table, we can see that,
Number of students playing Basketball from all the given school
A = 200 , B = 195 , C = 245 , D = 200 , E = 225
Number of students playing Cricket from all the given school
A = 150 , B = 200 , C = 250 , D = 230 , E = 200
Required difference = The total number of students playing Basketball from all the school - The total number of students playing Cricket from all the schoolCorrect Option: B
As per given table, we can see that,
Number of students playing Basketball from all the given school
A = 200 , B = 195 , C = 245 , D = 200 , E = 225
Number of students playing Cricket from all the given school
A = 150 , B = 200 , C = 250 , D = 230 , E = 200
The total number of students playing Basketball from all the school = 200 + 195 + 245 + 200 + 225 = 1065
The total number of students playing Cricket from all the school = 150 + 200 + 250 + 230 + 200 = 1030
Required difference = The total number of students playing Basketball from all the school - The total number of students playing Cricket from all the school
Required difference = 1065 − 1030 = 35
- The number of students playing Badminton from School E is p % of the students playing Badminton from School B. Then p equals :
-
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As per given table, we can see that,
Number of students playing Badminton from School E = 65
Number of students playing Badminton from School B = 130
According to Question ,
p % of Number of students playing Badminton from School B = Number of students playing Badminton from School E
⇒ p % of 130 = 65Correct Option: B
As per given table, we can see that,
Number of students playing Badminton from School E = 65
Number of students playing Badminton from School B = 130
According to Question ,
p % of Number of students playing Badminton from School B = Number of students playing Badminton from School E
⇒ p % of 130 = 65130 × p = 65 100 ⇒ p = 65 x 100 = 50 130
- The number of students playing Football from School C is a % of the total number of students playing Football from all the schools. Then a equals
-
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As per given table, we can see that,
Number of students playing football from all the given school
A = 250 , B = 125 , C = 175 , D = 100 , E = 250
Total number of students playing football all the school = 250 + 125 + 175 + 100 + 250 = 900
Now, According to question,
a % of 900 = 175Correct Option: B
As per given table, we can see that,
Number of students playing football from all the given school
A = 250 , B = 125 , C = 175 , D = 100 , E = 250
Total number of students playing football all the school = 250 + 125 + 175 + 100 + 250 = 900
Now, According to question,
a % of 900 = 175∴ a × 900 = 175 100 ∴ a = 175 = 19 4 % 9 9
- What is the total number of students from all schools who play cricket?
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Total number of students for cricket = Number of students play cricket from schools ( A + B + C + D + E )
Correct Option: B
Total number of students for Cricket = Number of students play cricket from schools ( A + B + C + D + E )
Total number of students for Cricket = 150 + 200 + 250 + 230 + 200
Total number of students for Cricket = 1030
Direction: Read the following information carefully and answer the questions based on it.
- What was the number of students studying in school B in 1994?
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Number of students studying in school B in 1994 = 950 + (350 − 150) + (225 − 115) + (185 − 110) + (200 − 90) = 950 + 200 + 110 + 75 + 110 = 1445.
Correct Option: C
Number of students studying in school B in 1994 = 950 + (350 − 150) + (225 − 115) + (185 − 110) + (200 − 90) = 950 + 200 + 110 + 75 + 110 = 1445.