Speed, Time and Distance
- The ratio between the speeds of two buses is 5 : 3. If the 1st bus runs 400 km in 8 h, then find the speed of the 2nd bus.?
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Let speed of 1st bus = 5k
and speed of 2nd bus = 3k
According to the question,
5k = 400/8 = 50Correct Option: A
Let speed of 1st bus = 5k
and speed of 2nd bus = 3k
According to the question,
5k = 400/8 = 50
∴ k = 50/5 = 10
∴ Speed of 2nd bus = 3k = 3 x 10 = 30 km/h
- The speeds of three cars are in the ratio of 2 : 3 : 5 find the ratio of the time taken by the above cars to travel the same distance.?
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We know that speed and time are inversely proportional.
∴ Ratio of time taken = 1/2 : 1/3 : 1/5Correct Option: A
We know that speed and time are inversely proportional.
∴ Ratio of time taken = 1/2 : 1/3 : 1/5
= 30/2 : 30/3 : 30/5 [ LCM of 2, 3, 5 = 30 ]
= 15 : 10 : 6
- Nilu covers a distance by walking for 6 h. While returning, his speed decreases by 2km/h and he takes 9 h to cover the same distance. What was her speed while returning?
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Let the speed in return journey = x
According to the question,
6( x + 2 ) = 9xCorrect Option: C
Let the speed in return journey = x
According to the question,
6( x + 2 ) = 9x
⇒ 6x + 12 = 9x
⇒ 9x - 6x = 12
⇒ 3x = 12
∴ x = 12/3 = 4km/h
- A takes 4 h more than the time taken by B to walk D km. If A doubles his speed, he can make it in 2 h less than that of B. How much time does B require for walking D km?
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Let B takes x h to walk D km.
Then, A takes ( x + 4 ) h to walk D km.
With doube of the speed,
A will take ( x+ 4)/2 h.
According to the question,
x - (x + 4)/2 = 2Correct Option: A
Let B takes x h to walk D km.
Then, A takes ( x + 4 ) h to walk D km.
With doube of the speed,
A will take ( x+ 4)/2 h.
According to the question,
x - (x + 4)/2 = 2
⇒ 2x - (x + 4) = 4
⇒ 2x - x - 4 = 4
∴ x = 4 + 4 = 8 h
- If Sohail walks from his home to office at 16 km/h, he is late by 5 min. If he walks at 20 km/h, he reaches 10 min before the office time. Find the distance of his office from his house.
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Let required distance = L
According to the question,
L/16 - L/20 = 15/20Correct Option: B
Let required distance = L
According to the question,
L/16 - L/20 = 15/20
⇒ (5L - 4L)/80 = 1/4
∴ L = (1/4) x 80 = 20 km