Speed, Time and Distance
- A thief steals a car at 1:30 p.m. and drives it at 45 km an hour. The theft is discovered at 2 p.m. and the owner sets off in another car at 50 km an hour. He will overtake the thief at ?
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Distance covered by thief in (1/2 ) hour = 20 km.
Now , 20 km is compensated by the owner at a relative speed of 10 km/hr in 2 hours. So, he overtake the thief at 4 p.m.Correct Option: B
Distance covered by thief in (1/2 ) hour = 20 km.
Now , 20 km is compensated by the owner at a relative speed of 10 km/hr in 2 hours so, he overtake the thief at 4 p.m.
- Ram travels a certain distance at 3 km/hr and reaches 15 min late. If he travels at 4 km/hr he reaches 15 min earlier. The distance he has to travel is ?
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Let the distance be x km.
Then, x/3 - x/4 = 30/60Correct Option: B
Let the distance be x km.
Then, x/3 - x/4 = 30/60
⇒ (4x - 3x ) / 12 = 1/2
∴ x = 6 km.
- A is twice as fast as B and B is thrice as fact as C is . The journey covered by C in 42 minute, will be covered by A in ?
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Let C' s speed = x km/hr.
Then, B's speed = 3x km/hr.
and A's speed = 6x km/hr.
∴ Ratio of speed of A, B, C
= 6x : 3x : x = 6 : 3 : 1
Ratio of times taken = 1/6 : 1/3 : 1 or 1 : 2 : 6Correct Option: D
Let C' s speed = x km/hr.
Then, B's speed = 3x km/hr.
and A's speed = 6x km/hr.
∴ Ratio of speed of A, B, C
= 6x : 3x : x = 6 : 3 : 1
Ratio of times taken = 1/6 : 1/3 : 1 or 1 : 2 : 6
∵ 6 : 1 : : 42 : t
⇒ 6t = 42
⇒ t = 7 min.
- A certain distance is covered at a certain speed. If half of this distance is covered in double the time, the ratio of the two speed is ?
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Let x km . be covered in y hrs.
then, 1st speed = (x / y) km/hr.
2nd speed = [(x/2) / 2y)] km/hr.
= (x/4y) km/hr.Correct Option: A
Let x km . be covered in y hrs.
then, 1st speed = (x / y) km/hr.
2nd speed = [(x/2) / 2y)] km/hr.
= (x/4y) km/hr.
∴ Ratio of speed = x/y : x/4y = 1 :1/4 = 4: 1
- A man walking at 3km/hr crosses a square field diagonally in 2 min. The area of the field is ?
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speed = 3 x ( 5/18 ) m/sec.
= 5 / 6 m/sec.
∴ Distance covered in 2 min. = ( 5 / 6) x 2 x 60 m
= 100 m.
∴ Length of diagonal = 100 mCorrect Option: C
speed = 3 x ( 5/18 ) m/sec.
= 5 / 6 m/sec.
∴ Distance covered in 2 min. = ( 5 / 6) x 2 x 60 m
= 100 m.
∴ Length of diagonal = 100 m
Area of the field = 1/2 x diagonal2
=1/2 x 100 x 100 m2
= 5000 m2
= 50 acres.