Speed, Time and Distance


  1. A thief steals a car at 1:30 p.m. and drives it at 45 km an hour. The theft is discovered at 2 p.m. and the owner sets off in another car at 50 km an hour. He will overtake the thief at ?









  1. View Hint View Answer Discuss in Forum

    Distance covered by thief in (1/2 ) hour = 20 km.
    Now , 20 km is compensated by the owner at a relative speed of 10 km/hr in 2 hours. So, he overtake the thief at 4 p.m.

    Correct Option: B

    Distance covered by thief in (1/2 ) hour = 20 km.
    Now , 20 km is compensated by the owner at a relative speed of 10 km/hr in 2 hours so, he overtake the thief at 4 p.m.


  1. Ram travels a certain distance at 3 km/hr and reaches 15 min late. If he travels at 4 km/hr he reaches 15 min earlier. The distance he has to travel is ?









  1. View Hint View Answer Discuss in Forum

    Let the distance be x km.
    Then, x/3 - x/4 = 30/60

    Correct Option: B

    Let the distance be x km.
    Then, x/3 - x/4 = 30/60
    ⇒ (4x - 3x ) / 12 = 1/2
    ∴ x = 6 km.



  1. A is twice as fast as B and B is thrice as fact as C is . The journey covered by C in 42 minute, will be covered by A in ?









  1. View Hint View Answer Discuss in Forum

    Let C' s speed = x km/hr.
    Then, B's speed = 3x km/hr.
    and A's speed = 6x km/hr.

    ∴ Ratio of speed of A, B, C
    = 6x : 3x : x = 6 : 3 : 1

    Ratio of times taken = 1/6 : 1/3 : 1 or 1 : 2 : 6

    Correct Option: D

    Let C' s speed = x km/hr.
    Then, B's speed = 3x km/hr.
    and A's speed = 6x km/hr.

    ∴ Ratio of speed of A, B, C
    = 6x : 3x : x = 6 : 3 : 1

    Ratio of times taken = 1/6 : 1/3 : 1 or 1 : 2 : 6

    ∵ 6 : 1 : : 42 : t
    ⇒ 6t = 42
    ⇒ t = 7 min.


  1. A certain distance is covered at a certain speed. If half of this distance is covered in double the time, the ratio of the two speed is ?









  1. View Hint View Answer Discuss in Forum

    Let x km . be covered in y hrs.
    then, 1st speed = (x / y) km/hr.

    2nd speed = [(x/2) / 2y)] km/hr.
    = (x/4y) km/hr.

    Correct Option: A

    Let x km . be covered in y hrs.
    then, 1st speed = (x / y) km/hr.

    2nd speed = [(x/2) / 2y)] km/hr.
    = (x/4y) km/hr.

    ∴ Ratio of speed = x/y : x/4y = 1 :1/4 = 4: 1



  1. A man walking at 3km/hr crosses a square field diagonally in 2 min. The area of the field is ?









  1. View Hint View Answer Discuss in Forum

    speed = 3 x ( 5/18 ) m/sec.
    = 5 / 6 m/sec.

    ∴ Distance covered in 2 min. = ( 5 / 6) x 2 x 60 m
    = 100 m.

    ∴ Length of diagonal = 100 m

    Correct Option: C

    speed = 3 x ( 5/18 ) m/sec.
    = 5 / 6 m/sec.

    ∴ Distance covered in 2 min. = ( 5 / 6) x 2 x 60 m
    = 100 m.

    ∴ Length of diagonal = 100 m

    Area of the field = 1/2 x diagonal2
    =1/2 x 100 x 100 m2
    = 5000 m2
    = 50 acres.