Elementary Algebra
- The area of the triangle formed by the lines 5x + 7y = 35, 4x + 3y = 12 and x-axis is
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Given that :- 5x + 7y = 35... (i)
4x + 3y = 12... (ii)
By equation (i) × 4 – (ii) × 5
On subtracting (20x + 28y = 140) - (20x + 15y = 60) ⇒ 13y = 80⇒ y = 80 = Height of triangle 13
Point of intersection on x-axis of equation
5x + 7y = 35
⇒ 5x + 7 × 0 = 35
⇒ 5x = 35 ⇒ x = 7
∴ (7, 0)
Similarly, point of intersection of
4x + 3y = 12 = (3, 0)
∴ Base = 7 – 3 = 4
Correct Option: A
Given that :- 5x + 7y = 35... (i)
4x + 3y = 12... (ii)
By equation (i) × 4 – (ii) × 5
On subtracting (20x + 28y = 140) - (20x + 15y = 60) ⇒ 13y = 80⇒ y = 80 = Height of triangle 13
Point of intersection on x-axis of equation
5x + 7y = 35
⇒ 5x + 7 × 0 = 35
⇒ 5x = 35 ⇒ x = 7
∴ (7, 0)
Similarly, point of intersection of
4x + 3y = 12 = (3, 0)
∴ Base = 7 – 3 = 4∴ Area = 1 × 4 × 80 = 160 sq.unit 2 13 13
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Minimum value of x2 + 1 - 3 is x2 + 1
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As per the given question ,
x2 + 1 - 3 x2 + 1
is minimum when x = 00 + 1 - 3 0 + 1 Correct Option: B
As per the given question ,
x2 + 1 - 3 x2 + 1
is minimum when x = 00 + 1 - 3 = - 2 0 + 1
- If x = a – b, y = b – c, z = c – a, then the numerical value of the algebraic expression x3 + y + z – 3xyz will be
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Here , x = a – b, y = b – c, z = c – a
We have x + y + z = a – b + b – c + c – a = 0Correct Option: B
Here , x = a – b, y = b – c, z = c – a
We have x + y + z = a – b + b – c + c – a = 0
∴ x3 + y + z – 3xyz = 0
Hence , the numerical value of algebraic expression is 0 .
- The shaded region represents
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The shaded region represents
y ≤ xCorrect Option: A
The shaded region represents
y ≤ x
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If 4x = 18y, then the value of x - 1 is y
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Here , 4x = 18y
⇒ x = 18 = 9 y 4 2
Correct Option: B
Here , 4x = 18y
⇒ x = 18 = 9 y 4 2 ∴ x - 1 = 9 - 1 = 7 y 2 2