If x = a – b, y = b – c, z = c – a, then the numerical

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If x = a – b, y = b – c, z = c – a, then the numerical value of the algebraic expression x³ + y + z – 3xyz will be

1. a + b + c
2. 0
3. 4 (a + b + c)
4. 3 abc

Correct Option: B

Here , x = a – b, y = b – c, z = c – a
We have x + y + z = a – b + b – c + c – a = 0
∴ x³ + y + z – 3xyz = 0
Hence , the numerical value of algebraic expression is 0 .