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A 50 Ω lossless T.L. has a pure reactance of j 100 Ω as its load. The VSWR in the live is—
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- 0
- ∞
- 50
- 100 + j 100
Correct Option: B
Reflection coefficient of the line,
| Γ = | |
| ZL + Z0 |
| = | = | ||
| j 100 + 50 | 2j + 1 |
and
| |Γ| = | = | = 1 | ||
| √(2)² + (1)² | √5 |
(˙.˙ we are interested in magnitude only)
Now,
| VSWR = | = | = | = ∞ | |||
| Γ – 1 | 1 – 1 | 0 |
