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A 220 V 1400 rpm, 40 A separately excited dc motor has an armature resistance of 0.4Ω. The motor is fed from a single phase circulating current dual converter with an input ac line voltage of 220 V (rms). The approximate firing angles of the dual converter for motoring operation at 50% of rated torque and 1000 rpm will be
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- 43°, 137°
- 43°, 47°
- 39°, 141°
- 39°, 51°
Correct Option: C
At rated speed and torque, E = V – Ia Ra= 220 – 40 × 0.4 = 204 volts
At 1000 rpm and 50% of rated torque, since
T ∝ I
I2 = | × 40 = 20 A | |
2 |
∴ E2 = | × N2 | |
N1 |
= | × 1000 = 145.71 volts | |
1400 |
∴ Applied Voltage, V2 = E2 + I 2 R2
= 145.71 + 20 × 0.4 = 153.71 volts
Hence output of converter (rectifier 1),
V0 = | cos α1 = 153.71 | |
π |
∴ | cos α1 = 153.71 | |
π |
⇒ α1 = 39.1° ≈ 39°
∴ Firing angle of rectifier, α2 = 180 – α1 = 141°
Hence α1 = 39° and α2 = 141°