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A single phase voltage source inverter is feeding a purely inductive load as shown in the figure given below.
The inverter is operated at 50 Hz in 180° square wave mode. Assume that the load current does not have any dc component. The peak value of the inductor current i0 will be
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- 6.37 A
- 10 A
- 20 A
- 40 A
Correct Option: B
| T = | = | = | = 0.01 sec | |||
| ω | 2π50 | 100 |
And, for 0 < ωt < π,
| V0 = L | ||
| dt |
| ⇒ 200 = 0.1 |  |  | ||
| T |
⇒ 2IP = 2000T
⇒ IP = 10 Amps
