Direction: In a machining experiment, tool life was found to vary with the cutting speed in the following manner:
Cutting speed (m/min) | Tool life (minutes) |
60 | 81 |
90 | 36 |
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The exponent (n) and constant (k) of the Taylor's tool life equation are
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- n = 0.5. and k = 540
- n = 1 and k = 4860
- n = –1 and k = 0.74
- n = –0.5 and k = 1.155
Correct Option: A
According to Taylor’s equation
VTn = C
where, V = cutting speed in m/s
T = tool life (min)
C = constant (Taylors constant)
∴ V1T1n = V2T2n
or 60 × (81)n = 90 × (36)n
or | = | n | ||||
90 | 81 |
or | = | n | ||||
3 | 9 |
Taking log of both sides
log | = n log | ||
3 | 9 |
∴ n = | log | = 0.5 | |
3 | |||
log | |||
9 |
∴ Taylor’s constant C = V1T1n
= 60 × (81)0.5
= 60√81= 60 × 9 = 540