Direction: In a machining experiment, tool life was found to vary with the cutting speed in the following manner:
Cutting speed (m/min) | Tool life (minutes) |
60 | 81 |
90 | 36 |
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What is the percentage increase in tool life when the cutting speed is halved?
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- 50%
- 200%
- 300%
- 400%
Correct Option: C
VTn = C
∴ Tn = | |
V |
or T = | 1/n | = | 2 | ||||||
V | V |
or T ∝ | |
V2 |
∴ | = | ||
T | V02 |
∴ | = | ||
T | V02 |
or | – 1 = 4 – 1 | |
T |
Hence percent increase = 300%
Alternately:
When cutting speed is halved
60 × (8.1)0.5 = | = (T2)0.5 | |
2 |
or | = (2)2 | |
81 |
or T2 =4 × 81
% change in tool life = | |
T1 |
= | × 100 | |
81 |
= 3 × | × 100 = 300% | |
81 |