Direction: A φ 40 mm job is subjected to orthogonal turning by a + 10° rake angle tool at 500 rev/min. By direct measurement during the cutting operation, the shear angle was found equal to 25°.
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If the friction angle at the tool chip interface is 58° 10' and the cutting force components measured by a dynamometer are 600 N and 200 N, the power loss due to friction (in kNm/ min) is approximately
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- 20
- 18
- 16
- 350
Correct Option: D
| r = | = | = | = 0.437 | |||
| T2 | V | 62.8 |
| = | , β = 58°10' | ||
| Fc | R cos(β - α) |
F = 764 N
loss of energy due to friction = F × Vc
= 764 × 27.5 = 350.3 Watts
