Direction: In an orthogonal cutting test, the following observations were made
Cutting force = 1200 N
Thrust force = 500 N
Tool rake angle = zero
Cutting speed = 1 m/s
Depth of cut = 0.8 mm
Chip thickness = 1.5 mm
-
Friction angle during machining will be
-
- 22.6
- 32.6
- 57.1
- 67.4
Correct Option: A
Fc = 1200 N FT = 500 N ∝ = 0 VC = 1 m/s d = t1 = 0.8 mm t2 = 1.5 mm
| tanβ = | + tan ∝ | ||
| Fc | |||
| 1 - | tan ∝ | ||
| Fc | |||
| tanβ = | + tan 0 | ||
| 1200 | |||
| 1 - | tan 0 | ||
| 1200 | |||
β = 22.62°
{chip Reductioncocfficient}
| = | ||
| t2 | V |
Vc = 0.533 × 1
Vc = 0.533m/s
