One kg of air (R = 287 J/kgK) undergoes an irreversible

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One kg of air (R = 287 J/kgK) undergoes an irreversible process between equilibrium state 1 (20°C, 0.9 m³) and equilibrium state 2 (20°C, 0.6 m³). The change in entropy s₂ – s₁ (in J/ kgK) is ______.

1. - 116.36 J /kgK
2. 116.36 J /kgK
3. - 117.36 J /kgK
4. 116.36 J /kgK

Correct Option: A

– 116.36 J/kg– K

∆ S = mRln	V₂
	V₁

= (287) (1) ln		0.6
		0.9

⇒ - 116.36 J/ kgK