If a pole of 12 m height casts a shadow of 4 √3 m

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If a pole of 12 m height casts a shadow of 4 √3 m long on the ground, then the sun’s angle of elevation at that instant is

1. 30°
2. 60°
3. 45°
4. 90° 16 cm is

Correct Option: B

AB = pole = 12 metre
Shadow = BC = 4 √3 metre
From ∆ABC,

tanθ =	AB
	BC

=	12	= √3
	4√3

⇒ tanθ = tan 60°
⇒ θ = 60°