If sin (3α – β) = 1 and cos (2α+β)

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sin (3 α – β) = 1 = sin 90°
⇒ 3α – β = 90° ... (i)

cos (2α + β) =	1	= cos 60°
	2

⇒ 2 α + β = 60° .... (ii)
By adding both equations,
3α + 2α = 90° + 60°
⇒ 5α = 150

⇒ α =	150	= 30°
	5

∴ tan α = tan 30° =	1
	√3