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If the angle of elevation of the sun decreases from 45° to 30°, then the length of the shadow of a pillar increases by 60m. The height of the pillar is
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- 60 (√3 + 1) metre
- 30 (√3 - 1) metre
- 30 (√3 + 1) metre
- 60 (√3 - 1) metre
Correct Option: C
AB = Height of pole = h metre
CD = 60 metre
In ∆ABC
tan 45° = | ⇒ 1 = | BC | BC |
⇒ BC = h metre
In ∆ABD,
tan 30° = | BD |
⇒ | = | √3 | h + 60 |
⇒ √3 h = h + 60
⇒ √3 h – h = 60
⇒ h (√3 - 1) = 60
⇒ h = | √3 - 1 |
= | = | = 90 | (√3 - 1)(√3 + 1) | 2 |
= 30 (√3 + 1) metre