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For the circuit shown in figure, the voltage Vs will be
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- 12 V
- 8 V
- 4 V
- 13 V
Correct Option: D
| Current in branch EF = | 1 | 1 amp | 1 |
| Current in Branch AB = | = | = 2 amp | 1Ω | 1 |
Current in branch CA = 1 + 2 = 3 amp.
| Current in CD = | = | 1 | 1 |
| = | 3 × 1 + 2 × 1 | 1 |
= 5amp
Current in branch GC = 5 + 3 = 8 amp
Now, Vs = VGC + VCD
= 1 × 8 + 1 × 5
= 13 V
