Ⅰ. 8x2 + 6x = 5 Ⅱ. 12y2

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Direction: In each of these questions, two equations are given. You have to solve these equations and find out the values of x and y and give answer
( 1 ) x < y
( 2 ) x > y
( 3 ) x ≤ y
( 4 ) x ≥ y
( 5 ) x = y

Ⅰ. 8x² + 6x = 5
Ⅱ. 12y² – 22y + 8 = 0

1. 1
2. 2
3. 3
4. 4
5. 5

Correct Option: C

According to question ,we can say that
Ⅰ. 8x² + 6x - 5 = 0
⇒ (4x + 5) (2x – 1) = 0

∴ x = -	5	or,	1
	4		2

Ⅱ. 12y² – 22y + 8 = 0
⇒ 6y² – 11y + 4 = 0
⇒ 2y( 3y – 4 ) - 1( 3y - 4 ) = 0
⇒ (2y – 1) (3y – 4) = 0

∴ y =	1	or,	4
	2		3

From above both equations it is clear that x ≤ y is required answer .