Ⅰ. 17x2 + 48x = 9 Ⅱ. 13y2 = 32y

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Direction: In each of these questions, two equations are given. You have to solve these equations and find out the values of x and y and give answer
( 1 ) x < y
( 2 ) x > y
( 3 ) x ≤ y
( 4 ) x ≥ y
( 5 ) x = y

Ⅰ. 17x² + 48x = 9
Ⅱ. 13y² = 32y – 12

1. 1
2. 2
3. 3
4. 4
5. 5

Correct Option: A

According to question ,we have
From equation Ⅰ.
17x² + 48x - 9 = 0
⇒ (x + 3)(17x – 3) = 0

∴ x = - 3 or,	3
	17

From equation Ⅱ.
13y² - 32y + 12 = 0
⇒ (y – 2)(13y – 6) = 0

∴ y = 2 or,	6
	13

Hence, required answer will be x < y .