Volume and Surface Area of Solid Figures


  1. The diameters of two cones are equal. If their slant heights be in the ratio of 5 : 7, then find the ratio of their curved surface areas. ?









  1. View Hint View Answer Discuss in Forum

    Given, l1/l2 = 5/7
    Now, curved surface area of the first cone = π rl1
    and curved surface area of second cone = πrl2

    Correct Option: D

    Given, l1/l2 = 5/7
    Now, curved surface area of the first cone = π rl1
    and curved surface area of second cone = πrl2
    ∴ Ratio = πrl1/πrl2 = l1/l2 = 5 : 7


  1. If the height of the right circular cone is increased by 200% and the radius of the base is reduced by 50%, then the volume of the cone ?









  1. View Hint View Answer Discuss in Forum

    Here, x = -50%, y = 200%
    According to the formula Net effect
    = [2x + y + x2 + 2xy/100 + x2y/1002] %

    Correct Option: D

    Here, x = -50%, y = 200%
    According to the formula Net effect
    = [2x + y + x2 + 2xy/100 + x2y/1002] %
    = [-100 + 200 + 2500 - 20000/100 + 500000/10000]%
    = [100 - 175 + 50] % = -25%



  1. If the volume of two right circular cones are in the ratio 1 : 3 and their diameters are in the ratio 3 : 5, then the ratio of their heights is ?









  1. View Hint View Answer Discuss in Forum

    Let diameter, radius and height of first cone are d1, r1 and h1, respectively and that of second cone are d2, r2 and h2, respectively.
    r1/r2 = d1/d2 = 3/5,
    h1/h2 = ?
    Given,
    [(1/3)πr21h1] / [(1/3)πr22h2] = 1/3
    ⇒ (3/5)2 x h1/h2 = 1/3

    Correct Option: A

    Let diameter, radius and height of first cone are d1, r1 and h1, respectively and that of second cone are d2, r2 and h2, respectively.
    r1/r2 = d1/d2 = 3/5,
    h1/h2 = ?
    Given,
    [(1/3)πr21h1] / [(1/3)πr22h2] = 1/3
    ⇒ (3/5)2 x h1/h2 = 1/3
    ⇒ h1/h2 = (1/3) x (25/9) = 25/27


  1. The ratio of the radius and height of a cone is 5 : 12. Its volume is 3142/7 cm3. Its slant height is ?









  1. View Hint View Answer Discuss in Forum

    Let radius = 5k, height = 12k
    According to the question
    = 1/3 x 22/7 x (5k)2 x 12k = 2200/7
    ⇒ k = 1
    ∴ r = 5, h = 12
    ∴ Slant height (l) = √r2 + h2

    Correct Option: B

    Let radius = 5k, height = 12k
    According to the question
    = 1/3 x 22/7 x (5k)2 x 12k = 2200/7
    ⇒ k = 1
    ∴ r = 5, h = 12
    ∴ Slant height (l) = √r2 + h2
    = √25 + 144
    = √169
    =13 cm



  1. The radius of the base of a right circular cone is increased by 15% keeping the height fixed. The volume of the cone will be increased by. ?









  1. View Hint View Answer Discuss in Forum

    Let the fixed height of a right circular cone is h and initial radius is r
    Then, initial volume of cone, V1 = (1/3)πr2h
    After increasing 15% radius of a cone = (r + 3r/20) = 23r/20
    New volume become, V2 = (1/3)π(23/20)2r2h
    ∴ Increasing percentage = [(V2 - V1) / V1] x 100

    Correct Option: C

    Let the fixed height of a right circular cone is h and initial radius is r
    Then, initial volume of cone, V1 = (1/3)πr2h
    After increasing 15% radius of a cone = (r + 3r/20) = 23r/20
    New volume become, V2 = (1/3)π(23/20)2r2h
    ∴ Increasing percentage = [(V2 - V1) / V1] x 100
    = {[(1/3)πr2h] / [(1/3)πr2h]} {(23/20)2 - 1} x 100
    = (23/20 + 1)(23/20 - 1) x 100
    = 43/20 x 3/20 x 100 = 32.25%