Volume = (1/3)πr²h
According to the question,
(1/3)πr²h = 100π
⇒ (1/3)πr² x 12 = 100π
⇒ r² = 25
∴ r = √25 = 5 cm
∴ Slant height (l) = √h² + r²

Correct Option: A

Volume = (1/3)πr²h
According to the question,
(1/3)πr²h = 100π
⇒ (1/3)πr² x 12 = 100π
⇒ r² = 25
∴ r = √25 = 5 cm
∴ Slant height (l) = √h² + r²
= √12² + 5²
= √169 = 13 cm

Volume of cone = (1/3)πr²h
= (1/3) x (22/7) x 10 x 10 x 21

Correct Option: A

Volume of cone = (1/3)πr²h
= (1/3) x (22/7) x 10 x 10 x 21 = 2200 cm³

Radius of cone (r) = 6/2 = 3 cm
and height of cone (h) = 4cm
Slant height (l) = √h² + r²
= √(4)² + (3)²
= √16 + 9
= 5 cm
Now, curved surface area = πrl

Correct Option: B

Radius of cone (r) = 6/2 = 3 cm
and height of cone (h) = 4cm
Slant height (l) = √h² + r²
= √(4)² + (3)²
= √16 + 9
= 5 cm
Now, curved surface area = πrl
= (22/7) x 3 x 5
= 330/7 = 47 cm²

Given that,
Diameter of a right circular cone = 7 cm
∴ Radius of a right circular cone = 7/2 cm
and slant height of a right circular cone (l) = 10 cm
∴ Lateral surface area of a cone = πrl = (22/7) x (7/2) x 10

Correct Option: A

Given that,
Diameter of a right circular cone = 7 cm
∴ Radius of a right circular cone = 7/2 cm
and slant height of a right circular cone (l) = 10 cm
∴ Lateral surface area of a cone = πrl = (22/7) x (7/2) x 10
= 11 x 10 = 110 cm²

volume = 48 π cm³ and h = 9 cm
∴ (1/3)πr²h = 48π
⇒ (1/3) x π x r² x 9 = 48π

Correct Option: A

volume = 48 π cm³ and h = 9 cm
∴ (1/3)πr²h = 48π
⇒ (1/3) x π x r² x 9 = 48π
∴ r² = (48π x 3) / (π x 9) = 16
∴ r = √16 = 4 cm
∴ Diameter = 2r = 2 x 4 = 8 cm