Sequences and Series
- For doing a certain job, boy is offered ₹ 5 on the first day, ₹ 15 on the second day, ₹ 45 on the third day and so no. How much will the boy earn at the end of seven days ?
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This is a GP with a = 5 , r = 15/5 = 3, n = 7
Sn = a(rn - 1 )/(r - 1)Correct Option: C
This is a GP with a = 5 , r = 15/5 = 3, n = 7
Sn = a(rn - 1 )/(r - 1)
⇒ S15 = 5(37 - 1)/(3 - 1)
= 5/2(37 - 1)
= 5/2 (2187 - 1)
= ₹ 5465
- Find the 10th term of the AP 13, 8, 3, -2,.......?
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In the given AP,
we have a = 13 , d = (8 - 13) = -5 and n = 10
Tn = a + (n - 1)dCorrect Option: A
In the given AP,
we have a = 13 , d = (8 - 13) = -5 and n = 10
Tn = a + (n - 1)d
T10 = 13 + (10 - 1) - 5
= 13 + 9 x (-5) = 13 - 45 = -32
- What term of the AP 10, 8, 6, 4, .... is - 28 ?
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We have, a = 10 , d = (8 - 10) = -2, Tn = - 28
Tn = a + (n - 1)dCorrect Option: D
We have, a = 10 , d = (8 - 10) = -2, Tn = - 28
Tn = a + (n - 1)d
⇒ -28 = 10 + (n - 1) x (- 2)
⇒ -28 = 10 - 2n + 2
⇒ 2n = 12 + 28
⇒ 2n = 40
∴ n = 20
- The 9th term exceeds the fifth term of an AP by 32. The sum of the ninth and fifth terms is 114. Find the eight term of the AP. ?
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T9 = a + (9 - 1)d = a + 8d
T5 = a + (5 - 1)d = a + 4d
T9 - T5 = 32
⇒ (a + 8d) - (a + 4d) = 32
⇒ 4d = 32
∴ d = 8
T9 + T5 = (a + 8d) + (a + 4d)
= 2a + 12d
T9 + T5 = 114
Correct Option: C
T9 = a + (9 - 1)d = a + 8d
T5 = a + (5 - 1)d = a + 4d
T9 - T5 = 32
⇒ (a + 8d) - (a + 4d) = 32
⇒ 4d = 32
∴ d = 8
T9 + T5 = (a + 8d) + (a + 4d)
= 2a + 12d
T9 + T5 = 114
⇒ 114 = 2(a + 6d)
⇒ a + 6d = 57
∴ T8 = a + 7d
= a + 6d + d
= 57 + 8 = 65
- What is the 11th term of the series 1, 8, 15, ... ?
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This is an AP with a = 1 and d = 7
∴ 11th term = a + (n - 1) x d = 1 + (11 - 1) x 7Correct Option: C
This is an AP with a = 1 and d = 7
∴ 11th term = a + (n - 1) x d = 1 + (11 - 1) x 7
= 1 + 10 x 7 = 71