Sequences and Series


  1. For doing a certain job, boy is offered ₹ 5 on the first day, ₹ 15 on the second day, ₹ 45 on the third day and so no. How much will the boy earn at the end of seven days ?









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    This is a GP with a = 5 , r = 15/5 = 3, n = 7
    Sn = a(rn - 1 )/(r - 1)

    Correct Option: C

    This is a GP with a = 5 , r = 15/5 = 3, n = 7
    Sn = a(rn - 1 )/(r - 1)
    ⇒ S15 = 5(37 - 1)/(3 - 1)
    = 5/2(37 - 1)
    = 5/2 (2187 - 1)
    = ₹ 5465


  1. Find the 10th term of the AP 13, 8, 3, -2,.......?









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    In the given AP,
    we have a = 13 , d = (8 - 13) = -5 and n = 10
    Tn = a + (n - 1)d

    Correct Option: A

    In the given AP,
    we have a = 13 , d = (8 - 13) = -5 and n = 10
    Tn = a + (n - 1)d
    T10 = 13 + (10 - 1) - 5
    = 13 + 9 x (-5) = 13 - 45 = -32



  1. What term of the AP 10, 8, 6, 4, .... is - 28 ?









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    We have, a = 10 , d = (8 - 10) = -2, Tn = - 28
    Tn = a + (n - 1)d

    Correct Option: D

    We have, a = 10 , d = (8 - 10) = -2, Tn = - 28
    Tn = a + (n - 1)d
    ⇒ -28 = 10 + (n - 1) x (- 2)
    ⇒ -28 = 10 - 2n + 2
    ⇒ 2n = 12 + 28
    ⇒ 2n = 40
    ∴ n = 20


  1. The 9th term exceeds the fifth term of an AP by 32. The sum of the ninth and fifth terms is 114. Find the eight term of the AP. ?









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    T9 = a + (9 - 1)d = a + 8d
    T5 = a + (5 - 1)d = a + 4d
    T9 - T5 = 32
    ⇒ (a + 8d) - (a + 4d) = 32
    ⇒ 4d = 32
    ∴ d = 8
    T9 + T5 = (a + 8d) + (a + 4d)
    = 2a + 12d
    T9 + T5 = 114

    Correct Option: C

    T9 = a + (9 - 1)d = a + 8d
    T5 = a + (5 - 1)d = a + 4d
    T9 - T5 = 32
    ⇒ (a + 8d) - (a + 4d) = 32
    ⇒ 4d = 32
    ∴ d = 8
    T9 + T5 = (a + 8d) + (a + 4d)
    = 2a + 12d
    T9 + T5 = 114
    ⇒ 114 = 2(a + 6d)
    ⇒ a + 6d = 57
    ∴ T8 = a + 7d
    = a + 6d + d
    = 57 + 8 = 65



  1. What is the 11th term of the series 1, 8, 15, ... ?









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    This is an AP with a = 1 and d = 7
    ∴ 11th term = a + (n - 1) x d = 1 + (11 - 1) x 7

    Correct Option: C

    This is an AP with a = 1 and d = 7
    ∴ 11th term = a + (n - 1) x d = 1 + (11 - 1) x 7
    = 1 + 10 x 7 = 71