Problems on Ages


  1. The sum of the ages of a father and son is 45 years. Five years ago the product of their ages was 4 times the father's age at that time. the present ages of the father's and son respectively are ?









  1. View Hint View Answer Discuss in Forum

    Let the present age of the father and son be x years and (45 - x)years respectively.
    Then, (x - 5)(45 - x - 5) = 4(x - 5)

    Correct Option: B

    Let the present age of the father and son be x years and (45 - x)years respectively.
    Then, (x - 5)(45 - x - 5) = 4(x - 5)
    ⇒ -x2 + 41x - 180 = 0
    ⇒ (x - 5)(x - 36) = 0
    ⇒ x = 36
    ∴ The present ages of father and son are 36 years and 9 years respectively.


  1. Shyam's age is 3 times that of Ramesh. After 12 years, Shyam's age will be double the age of Ramesh. Shyam's present age is ?









  1. View Hint View Answer Discuss in Forum

    Let Ramesh's present age be x years. Then Shyam's present age = 3x years.
    ∴ 2(x + 12) = (3x + 12)

    Correct Option: C

    Let Ramesh's present age be x years. Then Shyam's present age = 3x years.
    ∴ 2(x + 12) = (3x + 12)
    ⇒ x = 12
    Hence, Shyam's present age is 36 years.



  1. After 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older then B, the present age of B is ?









  1. View Hint View Answer Discuss in Forum

    Let the present ages of B and A be x years and (x + 9) years respectively.
    Then, (x + 9 + 10) = 2(x - 10)

    Correct Option: C

    Let the present ages of B and A be x years and (x + 9) years respectively.
    Then, (x + 9 + 10) = 2(x - 10)
    ∴ x = 39


  1. The sum of the ages of a son and father is 56 years. After four years, the age of the father will be three times that of the son. their present ages respectively are ?









  1. View Hint View Answer Discuss in Forum

    Let the present ages of son and father be x years and (56 - x) years respectively.
    Then, (56 - x + 4) = 3(x + 4)

    Correct Option: A

    Let the present ages of son and father be x years and (56 - x) years respectively.
    Then, (56 - x + 4) = 3(x + 4)
    ⇒ 4x = 48
    ⇒ x = 12
    So, their present ages are 12 years, 44 years respectively.



  1. Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4. What will be the total of their present ages ?









  1. View Hint View Answer Discuss in Forum

    Let A's age 10 years ago = x years
    Then, B's age 10 years ago = 2x years
    ∵ (x + 10) / (2x + 10) = 3 / 4

    Correct Option: C

    Let A's age 10 years ago = x years
    Then, B's age 10 years ago = 2x years
    ∵ (x + 10) / (2x + 10) = 3 / 4
    ⇒ 4(x + 10) = 3(2x + 10)
    ⇒ x(6 - 4) = 40 - 30
    ⇒ x = 5

    &ther4; Total of their present ages = (x + 10) + (2x + 10)
    = (3x + 20)
    = 35 years