Problems on Ages
- The sum of the ages of a father and son is 45 years. Five years ago the product of their ages was 4 times the father's age at that time. the present ages of the father's and son respectively are ?
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Let the present age of the father and son be x years and (45 - x)years respectively.
Then, (x - 5)(45 - x - 5) = 4(x - 5)Correct Option: B
Let the present age of the father and son be x years and (45 - x)years respectively.
Then, (x - 5)(45 - x - 5) = 4(x - 5)
⇒ -x2 + 41x - 180 = 0
⇒ (x - 5)(x - 36) = 0
⇒ x = 36
∴ The present ages of father and son are 36 years and 9 years respectively.
- Shyam's age is 3 times that of Ramesh. After 12 years, Shyam's age will be double the age of Ramesh. Shyam's present age is ?
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Let Ramesh's present age be x years. Then Shyam's present age = 3x years.
∴ 2(x + 12) = (3x + 12)Correct Option: C
Let Ramesh's present age be x years. Then Shyam's present age = 3x years.
∴ 2(x + 12) = (3x + 12)
⇒ x = 12
Hence, Shyam's present age is 36 years.
- After 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older then B, the present age of B is ?
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Let the present ages of B and A be x years and (x + 9) years respectively.
Then, (x + 9 + 10) = 2(x - 10)Correct Option: C
Let the present ages of B and A be x years and (x + 9) years respectively.
Then, (x + 9 + 10) = 2(x - 10)
∴ x = 39
- The sum of the ages of a son and father is 56 years. After four years, the age of the father will be three times that of the son. their present ages respectively are ?
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Let the present ages of son and father be x years and (56 - x) years respectively.
Then, (56 - x + 4) = 3(x + 4)Correct Option: A
Let the present ages of son and father be x years and (56 - x) years respectively.
Then, (56 - x + 4) = 3(x + 4)
⇒ 4x = 48
⇒ x = 12
So, their present ages are 12 years, 44 years respectively.
- Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4. What will be the total of their present ages ?
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Let A's age 10 years ago = x years
Then, B's age 10 years ago = 2x years
∵ (x + 10) / (2x + 10) = 3 / 4Correct Option: C
Let A's age 10 years ago = x years
Then, B's age 10 years ago = 2x years
∵ (x + 10) / (2x + 10) = 3 / 4
⇒ 4(x + 10) = 3(2x + 10)
⇒ x(6 - 4) = 40 - 30
⇒ x = 5
&ther4; Total of their present ages = (x + 10) + (2x + 10)
= (3x + 20)
= 35 years