Problems on Ages
- The age of the father 4 years ago was 5 times the age of his son. If the sum of their present ages is 44 years. What is the present age of his son ?
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Let the present age of father and son be x and y years respectively.
From 1st condition,
(x - 4) = 5(y- 4)
⇒ x - 4 = 5y - 20
⇒ x - 5y = -16 .....(i)
From 2nd condition,
⇒ x + y = 44 ...(ii)Correct Option: B
Let the present age of father and son be x and y years respectively.
From 1st condition,
(x - 4) = 5(y- 4)
⇒ x - 4 = 5y - 20
⇒ x - 5y = -16 .....(i)
From 2nd condition,
⇒ x + y = 44 ...(ii)
From equation (i) and (ii)
-6y = -60
⇒ y = 10
∴ Present age of son = 10 years
- In ten years, A will be twice as old as B was 10 years ago. If A is now 9 years older then B. Find the present age of B ?
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Let B's present age be x years then A's present age be (x + 9) years
As per the given condition
(x + 9 + 10) = 2(x - 10)Correct Option: A
Let B's present age be x years then A's present age be (x + 9) years
As per the given condition
(x + 9 + 10) = 2(x - 10)
⇒ x = 39
∴ The present age of B = 39 years
- The total ages of A, B and C at present is 90 years. Ten years ago the ratio of their ages was 1 : 2 : 3. Then the present age of B is .... ?
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Let the respective ages of A, B and C, ten years ago be x, 2x and 3x years.
∵ (x + 10) + (2x + 10) + ( 3x + 10) = 90Correct Option: A
Let the respective ages of A, B and C, ten years ago be x, 2x and 3x years.
∵ (x + 10) + (2x + 10) + ( 3x + 10) = 90
⇒ 6x = 60
⇒ x = 10
∴ B's present age = 2x + 10 = 30 years
- A father's age is four times as much as the sum of the ages of his three children but 6 years hence his age will be only double the sum of their ages. Then the age of the father is ?
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Let father's age be x years and the sum of ages of children be y years.
∵ x = 4 y ....(i)
Also (x + 6) = 2(y + 6 + 6 + 6) ....(ii) [6 is added thrice for three children ]Correct Option: C
Let father's age be x years and the sum of ages of children be y years.
∵ x = 4 y ....(i)
Also (x + 6) = 2(y + 6 + 6 + 6) ....(ii) [6 is added thrice for three children ]
Solving (i) and (ii)
x = 60 years, and y = 15 years.
- Two trains of length 50 m and 65 m are moving in the same direction at 18 m/s and 17 m/s, respectively. Find the time taken by the faster train to cross the slower train. ?
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According to the formula.
Required time = (x + y)/(u - v)
Here , x = 50 m , y = 65 m , u = 18 m/s and v = 17 m/sCorrect Option: D
According to the formula.
Required time = (x + y)/(u - v)
Here , x = 50 m , y = 65 m , u = 18 m/s and v = 17 m/s
∴ Required time = (50 + 65)/(18 - 17) = 115/ 1 = 115 s