Problems on Ages


  1. The age of the father 4 years ago was 5 times the age of his son. If the sum of their present ages is 44 years. What is the present age of his son ?









  1. View Hint View Answer Discuss in Forum

    Let the present age of father and son be x and y years respectively.

    From 1st condition,
    (x - 4) = 5(y- 4)
    ⇒ x - 4 = 5y - 20
    ⇒ x - 5y = -16 .....(i)

    From 2nd condition,
    ⇒ x + y = 44 ...(ii)

    Correct Option: B

    Let the present age of father and son be x and y years respectively.

    From 1st condition,
    (x - 4) = 5(y- 4)
    ⇒ x - 4 = 5y - 20
    ⇒ x - 5y = -16 .....(i)

    From 2nd condition,
    ⇒ x + y = 44 ...(ii)

    From equation (i) and (ii)
    -6y = -60
    ⇒ y = 10

    ∴ Present age of son = 10 years


  1. In ten years, A will be twice as old as B was 10 years ago. If A is now 9 years older then B. Find the present age of B ?









  1. View Hint View Answer Discuss in Forum

    Let B's present age be x years then A's present age be (x + 9) years
    As per the given condition
    (x + 9 + 10) = 2(x - 10)

    Correct Option: A

    Let B's present age be x years then A's present age be (x + 9) years
    As per the given condition
    (x + 9 + 10) = 2(x - 10)
    ⇒ x = 39

    ∴ The present age of B = 39 years



  1. The total ages of A, B and C at present is 90 years. Ten years ago the ratio of their ages was 1 : 2 : 3. Then the present age of B is .... ?









  1. View Hint View Answer Discuss in Forum

    Let the respective ages of A, B and C, ten years ago be x, 2x and 3x years.
    ∵ (x + 10) + (2x + 10) + ( 3x + 10) = 90

    Correct Option: A

    Let the respective ages of A, B and C, ten years ago be x, 2x and 3x years.
    ∵ (x + 10) + (2x + 10) + ( 3x + 10) = 90
    ⇒ 6x = 60
    ⇒ x = 10
    ∴ B's present age = 2x + 10 = 30 years


  1. A father's age is four times as much as the sum of the ages of his three children but 6 years hence his age will be only double the sum of their ages. Then the age of the father is ?









  1. View Hint View Answer Discuss in Forum

    Let father's age be x years and the sum of ages of children be y years.
    ∵ x = 4 y ....(i)
    Also (x + 6) = 2(y + 6 + 6 + 6) ....(ii) [6 is added thrice for three children ]

    Correct Option: C

    Let father's age be x years and the sum of ages of children be y years.
    ∵ x = 4 y ....(i)
    Also (x + 6) = 2(y + 6 + 6 + 6) ....(ii) [6 is added thrice for three children ]

    Solving (i) and (ii)
    x = 60 years, and y = 15 years.



  1. Two trains of length 50 m and 65 m are moving in the same direction at 18 m/s and 17 m/s, respectively. Find the time taken by the faster train to cross the slower train. ?









  1. View Hint View Answer Discuss in Forum

    According to the formula.
    Required time = (x + y)/(u - v)
    Here , x = 50 m , y = 65 m , u = 18 m/s and v = 17 m/s

    Correct Option: D

    According to the formula.
    Required time = (x + y)/(u - v)
    Here , x = 50 m , y = 65 m , u = 18 m/s and v = 17 m/s
    ∴ Required time = (50 + 65)/(18 - 17) = 115/ 1 = 115 s