Let B;s age 2 years ago be N years
∴ A's present age = 2N years

From question, 2N - (N + 2) = 2

Correct Option: C

Let B;s age 2 years ago be N years
∴ A's present age = 2N years

From question, 2N - (N + 2) = 2
⇒ N = 4
∴ A's age = 2 x 4 = 8 years

Let the age of A be (x - 3) years
⇒ B's age = x years
⇒ C's age = (x - 3) + 2 = x - 1

Correct Option: C

Let the age of A be (x - 3) years
⇒ B's age = x years
⇒ C's age = (x - 3) + 2 = x - 1
∴ B's age - C's age = x - (x - 1) = 1 year
∴ B is one year older then C.

Suppose x years later the father will be twice as old as his son.
∵ x + 41 = 2 (x + 16)

Correct Option: B

Suppose x years later the father will be twice as old as his son.
∵ x + 41 = 2 (x + 16)
⇒ x = 41 - 32 = 9 years

Let the age of B be N years
According to the question
∵ N + 20 = 6N

Correct Option: A

Let the age of B be N years
According to the question
∵ N + 20 = 6N
∴ N = 4 years
∴ A's age = 4 x 6 = 24 years and B's age = 4 years

Let the son's present age be x years
Then, (x + 4 ) + (4x + 4) = 43

Correct Option: B

Let the son's present age be x years
Then, (x + 4 ) + (4x + 4) = 43
⇒ 5x = 35
⇒ x = 7 years