Let Sarita;s present age = k yr
Then, Kavita's present age = 2k yr
According to the question,
(2k + 8) / (k + 8) = 22/13

Correct Option: D

Let Sarita;s present age = k yr
Then, Kavita's present age = 2k yr
According to the question,
(2k + 8) / (k + 8) = 22/13
⇒ 26k + 104 = 22k + 176
⇒ 4k = 72
∴ k = 18
Hence, Kavita's age = 2 x 18 = 36 yr

Let the ages of A and B 10 yr before were 13k yr and 17k yr, respectively.
Then, present age of A = 13k + 10
and present age of B = 17k + 10

According to the question,
∵ (13k + 10 + 17) / (17k + 10 + 17) = 10/11

Correct Option: C

Let the ages of A and B 10 yr before were 13k yr and 17k yr, respectively.
Then, present age of A = 13k + 10
and present age of B = 17k + 10

According to the question,
∵ (13k + 10 + 17) / (17k + 10 + 17) = 10/11
⇒ (13k + 27) / (17k + 27) = 10/11
⇒ 143k + 297 = 170k + 270
⇒ 27k = 27
∴ k = 1
Hence, present age of B = 17 x 1 + 10 = 27 yr

Let the present ages of mother and her daughter are ( x + 25 ) and x years respectively ; then 6( x - 5 ) = x + 25 - 5 ⇒ 6x - 30 = x + 20

Correct Option: D

Let the present ages of mother and her daughter are ( x + 25 ) and x years respectively ; then 6( x - 5 ) = x + 25 - 5 ⇒ 6x - 30 = x + 20 ⇒ 5x = 50 ∴ x = 10
Hence, the age of the mother = 10 + 25 = 35 years

Let us assume x years ago, the ratio of their ages was 3 : 5.

Correct Option: B

Let us assume x years ago, the ratio of their ages was 3 : 5, then
According to question,
(40 - x)/(60 - x) = 3/5
⇒ (40 - x) 5 = 3 (60 - x)
⇒ 200 - 5x = 180 - 3x
⇒ 2x = 20
∴ x = 10 years

Required ratio = (36 - 8)/(24 - 8)

Correct Option: A

Required ratio = (36 - 8)/(24 - 8) = 28/16 = 7 : 4