Mensuration
- If the height and the radius of the base of a cone are each increased by 100%, then the volume of the cone becomes
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For original cone,
V = 1 πr²h 3
For the second cone,
r1 = 2r
h1 = 2h∴ V1 = 1 πr1²h1 3 = 1 π(2r)² × 2h 3 = 8 × 1 πr²h = 8 V 3 Correct Option: D
For original cone,
V = 1 πr²h 3
For the second cone,
r1 = 2r
h1 = 2h∴ V1 = 1 πr1²h1 3 = 1 π(2r)² × 2h 3 = 8 × 1 πr²h = 8 V 3
- If the radius of a right circular cylinder is decreased by 50% and its height is increased by 60%, its volume will be decreased by
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Let the radius of a right circular cylinder is changed by x% and height is changed y%, then Volume change by
2x + y + x² + 2xy + x²y % 100 100² ∴ Effective change = - 2 × 50 + 60 + 2500 - 6000 + 150000 % 100 10000
= (–100 + 60 – 35 + 15)
= (75 – 135) = – 60%
Negative sign shows decrease.Correct Option: B
Let the radius of a right circular cylinder is changed by x% and height is changed y%, then Volume change by
2x + y + x² + 2xy + x²y % 100 100² ∴ Effective change = - 2 × 50 + 60 + 2500 - 6000 + 150000 % 100 10000
= (–100 + 60 – 35 + 15)
= (75 – 135) = – 60%
Negative sign shows decrease.
- A copper sphere of diameter 18 cm is drawn into a wire of diameter 4 mm. The length of the wire, in metre, is :
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Volume of sphere = 4 πr³ 3 = 4 π × 9 × 9 × 9 3
= 972π cubic.cm.
If the length of wire be h cm., then
π × (0.2)² × h = 972π⇒ h = 972 = 24300 cm. 0.2 × 0.2
or 243 metresCorrect Option: B
Volume of sphere = 4 πr³ 3 = 4 π × 9 × 9 × 9 3
= 972π cubic.cm.
If the length of wire be h cm., then
π × (0.2)² × h = 972π⇒ h = 972 = 24300 cm. 0.2 × 0.2
or 243 metres
- Each of the radius of the base and the height of a right circular cylinder is increased by 10%. The volume of the cylinder is increased by
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Intial area of the cylinder = πr²h
Voiume of the new cylinder = p (1.1r)² × 1.1h
= 1.331 πr²h
∴ Increase in area = (1.331 – 1) πr²h
= 0.331 πr²h∴ Percentage increase = 0.331πr²h × 100 = 33.1 % πr²h Correct Option: C
Intial area of the cylinder = πr²h
Voiume of the new cylinder = p (1.1r)² × 1.1h
= 1.331 πr²h
∴ Increase in area = (1.331 – 1) πr²h
= 0.331 πr²h∴ Percentage increase = 0.331πr²h × 100 = 33.1 % πr²h
- If the height of a cone is increased by 100% then its volume is increased by :
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Volume of the cone = 1 πr²h, new height = 100%h 3
∴ Percentage increase in volume = 100%Correct Option: A
Volume of the cone = 1 πr²h, new height = 100%h 3
∴ Percentage increase in volume = 100%