Mensuration


  1. The area of two equilateral triangles are in the ratio 25 : 36. Their altitudes will be in the ratio :









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    The ratio of the area of two similar triangles is equal to the ratio of square of the corresponding altitudes.

    Ratio of altitudes =
    25
    =
    5
    366

    or 5 : 6

    Correct Option: C

    The ratio of the area of two similar triangles is equal to the ratio of square of the corresponding altitudes.

    Ratio of altitudes =
    25
    =
    5
    366

    or 5 : 6


  1. ABC is an equilateral triangle of side 2 cm. With A, B, C as centre and radius 1 cm three arcs are drawn. The area of the region within the triangle bounded by the three arcs is









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    Using Rule 17,

    Each angle of the triangle = 60°
    Required area of the three sectors

    = 3 ×
    60
    × π(i)²
    360

    =
    π
    cm²
    2

    Area of triangle =
    3
    × 4 = √3cm²
    4

    ∴ Required area = 3 -
    π
    cm²
    2

    Correct Option: C

    Using Rule 17,

    Each angle of the triangle = 60°
    Required area of the three sectors

    = 3 ×
    60
    × π(i)²
    360

    =
    π
    cm²
    2

    Area of triangle =
    3
    × 4 = √3cm²
    4

    ∴ Required area = 3 -
    π
    cm²
    2



  1. The area of a right-angled isosceles triangle having hypotenuse 16√2 cm is









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    Using Rule 1,

    Let AB = BC = x;
    AC = 16√2
    ∴ x² + x² = (16√2
    ⇒ 2x² = 16 × 16 × 2
    ⇒ x² = 16 × 16
    ⇒ x = 16

    ∴ Area of triangle =
    1
    × base × height
    2

    =
    1
    × 16 × 16 = 128cm²
    2

    Correct Option: B

    Using Rule 1,

    Let AB = BC = x;
    AC = 16√2
    ∴ x² + x² = (16√2
    ⇒ 2x² = 16 × 16 × 2
    ⇒ x² = 16 × 16
    ⇒ x = 16

    ∴ Area of triangle =
    1
    × base × height
    2

    =
    1
    × 16 × 16 = 128cm²
    2


  1. The sides of a triangle are in the ratio 2 : 3 : 4. The perimeter of the triangle is 18 cm. The area (in cm2) of the triangle is









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    Using Rule 2 and 3,
    Ratio = 2 : 3 : 4
    = 4 : 6 : 8 Perimeter = 18 cm

    ∴ Semi-perimeters =
    4 + 6 + 8
    = 9
    2

    ∴ Area of triangle = √s(s - a)(s - b)(s -c)
    = √9(9 - 4)(9 - 6)(9 - 8)
    = √9 × 5 × 3 × 1
    = 3√15sq.cm.

    Correct Option: D

    Using Rule 2 and 3,
    Ratio = 2 : 3 : 4
    = 4 : 6 : 8 Perimeter = 18 cm

    ∴ Semi-perimeters =
    4 + 6 + 8
    = 9
    2

    ∴ Area of triangle = √s(s - a)(s - b)(s -c)
    = √9(9 - 4)(9 - 6)(9 - 8)
    = √9 × 5 × 3 × 1
    = 3√15sq.cm.



  1. If the numerical value of the perimeter of an equilateral triangle is 3 times the area of it, then the length of each side of the triangle is









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    Using Rule 6,
    If the side of the equilateral triangle be x units, then,

    3x =√3
    3
    4

    ⇒ 3x =
    3x²
    4

    ⇒ x = 4 units

    Correct Option: C

    Using Rule 6,
    If the side of the equilateral triangle be x units, then,

    3x =√3
    3
    4

    ⇒ 3x =
    3x²
    4

    ⇒ x = 4 units