Logarithm
- If 100.3010 = 2, then find the value of log0.125 125. ?
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Exp. = log0.125125 = log2-3 53 = - 3/3log25 = -log25
∵ 100.3010 = 2
⇒ log102 = 0.3010
∵ log105 = log1010/2 = log1010-log102
= 1-0.3010 = 0.6990Correct Option: B
Exp. = log0.125125 = log2-3 53 = - 3/3log25 = -log25
∵ 100.3010 = 2
⇒ log102 = 0.3010
∵ log105 = log1010/2 = log1010-log102
= 1-0.3010 = 0.6990
∴ -log25 = - log105 / log102
= - 0.6990 / 0.3010 = - 699/301
- Find the value of log0.125 64 ?
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Exp. = log0.12564 = log2-3 26
={6 / (-3)} log22Correct Option: D
Exp. = log0.12564 = log2-3 26
={6 / (-3)} log22
= -2
- Find the value of log3228 + log24337 - log361296 ?
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Exp. =log3228 + log24337 - log361296
= log25 28 + log35 37 - log36 362
= (8/5)log22 + (7/5)log33 - 2log3636Correct Option: C
Exp. =log3228 + log24337 - log361296
= log25 28 + log35 37 - log36 362
= (8/5)log22 + (7/5)log33 - 2log3636
= 8/5 + 7/5 - 2 = 1
- Find the value of log49 16807 - log9 27 ?
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Exp. = log4916807 - log927
= log72 75 - log32 33
=(5/2)log77 - (3/2)log33Correct Option: B
Exp. = log4916807 - log927
= log72 75 - log32 33
=(5/2)log77 - (3/2)log33
=5/2 - 3/2
= 1