Algebra


  1. If x is a prime number and –1 ≤
    2x − 7
    ≤ 1 then the number of values of x is
    5









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    –1 ≤
    2x − 7
    ≤ 1
    5

    ⇒  –5 ≤ 2x – 7 ≤ 5
    ⇒  –5 + 7 ≤ 2x – 7 + 7 ≤ 5 + 7
    ⇒  2 ≤ 2x ≤ 12
    ⇒  1 ≤ x ≤ 6

    Correct Option: D

    –1 ≤
    2x − 7
    ≤ 1
    5

    ⇒  –5 ≤ 2x – 7 ≤ 5
    ⇒  –5 + 7 ≤ 2x – 7 + 7 ≤ 5 + 7
    ⇒  2 ≤ 2x ≤ 12
    ⇒  1 ≤ x ≤ 6


  1. a2 + b2 + c2 = 2 (a – b – c) – 3, then the value of (a + b + c) is









  1. View Hint View Answer Discuss in Forum

    a2 + b2 + c2 = 2a – 2b – 2c – 3
    ⇒  (a2 – 2a + 1) + (b2 + 2b + 1) + (c2 + 2c + 1) = 0
    ⇒  (a – 1)2 + (b + 1)2 + (c + 1)2 = 0
    ⇒  a = 1, b = –1, c = –1
    ∴  a + b + c = 1 – 1 – 1 = –1

    Correct Option: C

    a2 + b2 + c2 = 2a – 2b – 2c – 3
    ⇒  (a2 – 2a + 1) + (b2 + 2b + 1) + (c2 + 2c + 1) = 0
    ⇒  (a – 1)2 + (b + 1)2 + (c + 1)2 = 0
    ⇒  a = 1, b = –1, c = –1
    ∴  a + b + c = 1 – 1 – 1 = –1



  1. If x = 2 + √3 , then x2 +
    1
    is equal to
    x2









  1. View Hint View Answer Discuss in Forum

    x = 2 + √3

    ∴ 
    1
    =
    1
    x2 + √3

    =
    2 − √3
    (2 + √3)(2 − √3)

    =
    2 − √3
    = 2 − √3
    4 −3

    ∴ x2 +
    1
    = x +
    1
    2 − 2
    x2x

    = (2 + √3 + 2 − √3)2 – 2
    = 42 – 2 = 16 – 2 = 14

    Correct Option: D

    x = 2 + √3

    ∴ 
    1
    =
    1
    x2 + √3

    =
    2 − √3
    (2 + √3)(2 − √3)

    =
    2 − √3
    = 2 − √3
    4 −3

    ∴ x2 +
    1
    = x +
    1
    2 − 2
    x2x

    = (2 + √3 + 2 − √3)2 – 2
    = 42 – 2 = 16 – 2 = 14


  1. If a2 – 4a – 1 = 0, a ≠ 0, then the value of a2 + 3a +
    1
    3
    is
    a2a









  1. View Hint View Answer Discuss in Forum

    a2 – 4a – 1 = 0
    ⇒  a2 – 1 = 4a
    On dividing both sides by a,

    ⇒  a −
    1
    = 4   ...(i)
    a

    Expression = a2 + 3a +
    1
    3
    a2a

    = a2 +
    1
    + 3a −
    3
    a2a

    = a −
    1
    2 + 2 + 3 a −
    1
    aa

    = (4)2 + 2 + 3 × 4
    = 16 + 2 + 12 = 30

    Correct Option: D

    a2 – 4a – 1 = 0
    ⇒  a2 – 1 = 4a
    On dividing both sides by a,

    ⇒  a −
    1
    = 4   ...(i)
    a

    Expression = a2 + 3a +
    1
    3
    a2a

    = a2 +
    1
    + 3a −
    3
    a2a

    = a −
    1
    2 + 2 + 3 a −
    1
    aa

    = (4)2 + 2 + 3 × 4
    = 16 + 2 + 12 = 30



  1. What is the slope between the lines y − √3 x− 5 = 0 and √3y − x + 6 = 0









  1. View Hint View Answer Discuss in Forum

    Angle between two lines is

    tan θ =
    1
    3

    ∴  Slope =
    1
    3

    Correct Option: B

    Angle between two lines is

    tan θ =
    1
    3

    ∴  Slope =
    1
    3