Problem Based on ages


  1. Two years ago, the ratio of Ram's and Mohan's age was 3 : 2 and at present 7 : 5. What are their present ages?









  1. View Hint View Answer Discuss in Forum

    The ratio of Ram's and Mohan's present age is 7 : 5.
    Let us assume the present ages of Ram and Mohan are 7Y and 5Y years.

    Correct Option: A

    The ratio of Ram's and Mohan's present age is 7 : 5.
    Let us assume the present ages of Ram and Mohan are 7Y and 5Y years.
    2 Years ago the age of Ram and Mohan will be 7Y - 2 and 5Y - 2 years.
    According to question,
    Two years ago, the ratio of Ram's and Mohan's age was 3 : 2, then
    (7Y -2)/(5Y - 2) = 3/2
    ⇒ (7Y -2) x 2 = 3 x (5Y - 2)
    ⇒ 14Y - 4 = 15Y - 6
    ∴ Y = 2
    Hence, their present ages = 7 x 2 = 14 years and 5 x 2 = 10 year


  1. One year ago, the ratio of Yamini and Gamini's was 6 : 7 respectively. Four year hence, the ratio would become 7 : 8. Find the age of Gamini ?











  1. View Hint View Answer Discuss in Forum

    Let one year ago the ages of Yamini and Gamini were 6P and 7P years respectively.

    Correct Option: C

    Let one year ago the ages of Yamini and Gamini were 6P and 7P years respectively; then
    (6P + 5)/(7P + 5) = 7/8
    ⇒ (6P + 5) x 8 = 7 x (7P + 5)
    ⇒ 48P + 40 = 49P + 35
    ∴ P = 5
    Hence, present ago of Gamini = 7P + 1 = 7 x 5 + 1 = 36 years



  1. The ages of Surabhi and Neerja are in the ratio of 6 : 7 respectively. After 6 years the ratio of their ages will be 15 : 17. Find the age of Neerja.











  1. View Hint View Answer Discuss in Forum

    Let the present ages of Surabhi and Neerja are 6x and 7x years respectively.

    Correct Option: C

    Let the present ages of Surabhi and Neerja are 6x and 7x years respectively.
    According to question,
    (6x + 6)/(7x + 6) = 15/17
    ⇒ (6x + 6)x17 = 15x(7x + 6)
    ⇒ 102x + 102 = 105x + 90
    ⇒ 3x = 12
    ∴ x = 4
    Hence, present ages of Neerja = 7 x 4 = 28 years


  1. The average age of a woman and her daughter is 42 years. The ratio of their ages is 2 : 1 respectively. Find the daughter's age.











  1. View Hint View Answer Discuss in Forum

    Let the present ages of womon and her daugher be 2x and x years respectively .

    Correct Option: B

    Let us assume the present ages of woman and her daughter be 2x and x years respectively ; then
    According to question,
    The average age of a woman and her daughter is 42 years
    (2x + x)/2 = 42
    ⇒ 3x = 84
    ∴ x = 28
    Hence, present age of her daughter = 28 years



  1. The ages of A and B are in the ratio of 11 : 13 respectively. After 7 years the ratio of their ages will be 20 : 23. What is the difference in years between their ages?











  1. View Hint View Answer Discuss in Forum

    Let the present ages of A and B are 11x and 13x years respectively.

    Correct Option: C

    Let the present ages of A and B are 11x and 13x years respectively; then
    According to question,
    After 7 years the ratio of their ages will be 20 : 23.
    (11x + 7 ) / (13x + 7) = 20/23
    ⇒ (11x + 7 ) 23 = 20 (13x + 7)
    ⇒ 253x + 161 = 260x + 140
    ⇒ 7x = 21
    ∴ x = 3
    Hence, difference of their ages = 13x - 11x = 2x = 2 x 3 = 6 years