Steel structures miscellaneous

Steel structures miscellaneous

Easy Questions

Steel Structures

Steel structures miscellaneous
  1. An un-stiffened web I section is fabricated from a 10 mm thick plate by fillet welding as shown in the figure. If yield stress of steel is 250 MPa, the maximum shear load that section can take








  1. View Hint View Answer Discuss in Forum

    depth
    		=
    300 - 20
    		= 28 < 85
    thickness10

    V = d.tω.τva
    τva = 0.4 × 250
    = 100 N/mm2
    ∴ V = 300 × 10 × 100
    = 300 × 103 N
    = 300 kN

    Correct Option: D

    depth
    		=
    300 - 20
    		= 28 < 85
    thickness10

    V = d.tω.τva
    τva = 0.4 × 250
    = 100 N/mm2
    ∴ V = 300 × 10 × 100
    = 300 × 103 N
    = 300 kN

  1. A square steel slab base of are 1 m2 is provided for a column made of two rolled channel sections. The 300 mm × 300 mm column carries an axial compressive load of 2000 kN. The line of action of the load passed through the centroid of the column section as well as of the slab base. The permissible bending stress in the slab base is 185 MPa. The required minimum thickness of the slab base is








  1. View Hint View Answer Discuss in Forum

    Projection at sides,

    a = b =
    1000 - 300
    		= 350 mm
    2

    w =
    load applied
    area

    =
    2000 × 103
    		= 2 N/mm2
    (1000)2

    Thickness of slab,

    = 55 mm

    Correct Option: D

    Projection at sides,

    a = b =
    1000 - 300
    		= 350 mm
    2

    w =
    load applied
    area

    =
    2000 × 103
    		= 2 N/mm2
    (1000)2

    Thickness of slab,

    = 55 mm

  1. A strut in a steel truss is composed of two equal angles ISA 150 mm × 150 mm of thickness 100 mm connected back-toback to the same side of a gusset plate. The cross sectional area of each angle is 2921 mm2 and moment of inertia (Ixx = Iyy) is 6335000 mm4 . The distance of the centroid of the angle from its surface (Cx = Cy) is 40.8 mm. The minimum radius of gyration of the sturt is








  1. View Hint View Answer Discuss in Forum


    Total area, A = 2 × a = 2 × 2921 = 5842 mm2
    Minimum MI, Ixx = 2 × Ixx of each angle
    = 2 × 6335000 = 12670000 mm4

    Correct Option: C


    Total area, A = 2 × a = 2 × 2921 = 5842 mm2
    Minimum MI, Ixx = 2 × Ixx of each angle
    = 2 × 6335000 = 12670000 mm4

  1. Two equal angles ISA 100 mm × 100 mm of thickness 10 mm are placed back-to-back and connected to the either side ofa gusset plate through a single row of 16 mm diameter rivets in double shear.
    The effective areas of the connected and unconnected legs of each of these angles are 775 mm2 and 950 mm2 respectively. If these angles are NOT tackrivated, the net effective area of this pair of angles is








  1. View Hint View Answer Discuss in Forum

    As per IS, when two angles are not tack riverted, they will be considered as a single angle connected to one side of gusset plate
    Area of angle
    Connected leg: A1 = 775 mm2
    unconnected leg: A2 = 950 mm2

    K1 =
    3A1
    		=
    3 × 775
    3A1 + A23 × 775 + 950

    = 0.71
    Net area, Anet = 2 (A1 + k1 A2)
    = 2 (775 + 0.75 × 950)
    = 2899 mm2

    Correct Option: D

    As per IS, when two angles are not tack riverted, they will be considered as a single angle connected to one side of gusset plate
    Area of angle
    Connected leg: A1 = 775 mm2
    unconnected leg: A2 = 950 mm2

    K1 =
    3A1
    		=
    3 × 775
    3A1 + A23 × 775 + 950

    = 0.71
    Net area, Anet = 2 (A1 + k1 A2)
    = 2 (775 + 0.75 × 950)
    = 2899 mm2