Electrical machines miscellaneous
- A single-phase transformer is feeding a lagging load. What will be the effect on t he voltage regulation of the transformer if
(i) an inductor is connected in parallel to the load
(ii) a capacitor is connected in parallel to the load The regulation will
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NA
Correct Option: C
NA
- The magnetic core of a certain material is operated at constant flux density. If core losses measured at 50 Hz and 75 Hz are respectively 2000 W and 3375 W, the hysteresis and eddy current losses of the core at 100 Hz would respectively be
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NA
Correct Option: C
NA
- A torroidal ferromagnetic ring is uniformly wound with copper wire of certain turns. A dc voltage V1 is applied across the winding to cause a uniform flux density in the ring. If linear dimensions of the ring, number of turns and length of a mean turn are doubled without changing gauge of the wire, then dc voltage required to be applied across then new winding to produce same flux density will be
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NA
Correct Option: A
NA
- In electromechanical energy conversion device shown in the given figure, instantaneous values of armature induced emf, bus bar voltage and armature current are respectively e, v and i, Te, Ta and ωr represent external torque, armature developed torque and angular velocity of shaft respectively. Assume that given directions of parameters in the figure are positive. If device is working generating mode, then
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NA
Correct Option: C
NA
- The developed electromagnetic force and/or torque in electro-mechanical energy conversion systems act in a direction that tends to
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In the eletro-mechanical energy conversion system,
Mechanical energy output = electrical energy input – increase in stored energy
∴ Fƒdx = i dλ − dWƒ
where, Fƒ = torque developed
λ = flux linkages
Wƒ = stored energy
If flux is constant, then
dλ = 0
∴ Fƒdx = – dWƒ⇒ Fƒ = − dWƒ dx
From the above relation, torque developed will be in opposite direction of stored energy,Correct Option: B
In the eletro-mechanical energy conversion system,
Mechanical energy output = electrical energy input – increase in stored energy
∴ Fƒdx = i dλ − dWƒ
where, Fƒ = torque developed
λ = flux linkages
Wƒ = stored energy
If flux is constant, then
dλ = 0
∴ Fƒdx = – dWƒ⇒ Fƒ = − dWƒ dx
From the above relation, torque developed will be in opposite direction of stored energy,