-
A voltage 1000 sin ωt Volts is applied across YZ. Assuming ideal diodes, the voltage measured across WX in Volts is
-
- sin ωt
- (sin ωt + |sin ωt|) / 2
- (sin ωt - |sin ωt|) / 2
- 0 for all t
- sin ωt
Correct Option: D
‘D’ 0 for all +
Note :
⇒ All diode conducts only done negative half.
⇒ XW is at symmetrical point so voltage across XW is zero for all time.
