The average power delivered to an impedance (4 – j3) Ω

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The average power delivered to an impedance (4 – j3) Ω by a current 5 cos (100 πt + 100) A is

1. 44.2 W
2. 50 W
3. 62.5 W
4. 125 W

Correct Option: B

Z = 4 – j3 = R_L – jX_C; R_L = 4;
I = 5 cos (100πt + 100) = I_m cos² (ωt + α)

P =	1	I_m² .R_L =	1	× 5² × 4 = 50 W
	2		2