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Power electronics and drives miscellaneous

Power Electronics and Drives

  1. A lossy capacitor Cx, rated operation at 5 kV, 50 Hz is represented by an equivalent circuit with an ideal capacitor Cp is parallel with a resistor Rp. The value of Cp is found to be 0.102 μF and the value of Rp = 1.25 MΩ. Then the power loss and tan δ of the lossy capacitor operating at the rated voltage, respectively, are
    1. 10 W and 0.0002
    2. 10 W and 0.0025
    3. 20 W and 0.025
    4. 20 W and 0.04
Correct Option: C

Power - loss =
V2
(5 KV)2
= 20 W
RP1.25 MΩ

tan δ =
1
ωCP RP

=
1
= 0.025
(2π 50)(0.102 × 10-6)(1.25 × 106)




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