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A single-phase inverter is operated in PWM mode generating a single-pulse of width 2d in the centre of each half cycle as shown in the figure given below. It is found that the output voltage is free from 5th harmonic for pulse width 144°. What will be percentage of 3rd harmonic present in the output voltage (V03/Vo1 max)?
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- 0.0%
- 19.6%
- 31.7%
- 53.9%
- 0.0%
Correct Option: B
The output of single-phase inverter,
For pulse width of 144° , output is tree from
5th harmonic i.e., 2d = 144°
⇒ d = 72°
| Then , V01 = | sin 72° . sin ωt. sin | |||
| π | 2 |
| V03 = | sin(3 × 72°) . sin(3ωt) . sin |  |  | |||
| 3π | 2 |
| ratio , | = | | | .sin(216°) | ≈ 20% | |||
| 3π | ||||||||
| V01 , max | | | .sin(72°) | |||||
| π | ||||||||
